Formula= (y2-y1)/ (x2-x1)
(-5 - -1) / (-2 - -4)
(-4) / (2) = -2
q8 is C
(-3 - -3) / (8 - 4)
(0) / (4) = 0
q12 is D
If the volume is 108, and the height is 3 meters, you would divide 108 by 3 , which is 36.
Answer:
The equation for the object's height s at time t seconds after launch is s(t) = –4.9t2 + 19.6t + 58.8, where s is in meters. When does the object strike the ground.
Step-by-step explanation:
Answer: so the square root od 2 is 1 and 2
and the square root of 6 is 2 and 3
and idk the simplist for for it srry
Step-by-step explanation:
Yes what is the four question
