Answer:
t = 1.5 seconds
Step-by-step explanation:
Given that d = −4t^2 + 2t + 6,
where d = distance above the water and
t = seconds.
Let assume that it's a perfect parabola
At the symmetry
t = -b/2a
Where a = -4, b = 2
t = -2/2(-4)
t = 1/4
To determine how long it will take a diver to reach the water’s surface
d = −4t^2 + 2t + 6
At water surface d =0
4t^2 - 2t - 6 = 0
Factorizing the above equation leads to
4t^2 + 4t - 6t - 6 = 0
4t(t + 1) -6(t + 1) = 0
4t - 6 =0
4t = 6
t = 6/4= 3/2 = 1.5 seconds
Since t can't be negative so we ignore the second factor.
The correct answer is C. Divide both sides by 35
I'll show you
35x=88
35x/35 = 88/35
x=2.5
Speed of light in vacuum = 2.998 x 10^8 m/s
1m = 1/1000 km and 1s = 1/3600 hr
Speed of light in vacuum = (2.998 x 10^8 x (1/1000)
km) / (1/3600) hr
Speed of light in vacuum = 10.792 x 10^8 km/hr
Now
1km = 0.6213 mi
1hr = 60min
As Speed of light in vacuum = 10.792 x 10^8 km/hr
Speed of light in vacuum = 10.792 x 10^8 x (0.6213mi)
/ 60min
Speed of light in vacuum = 0.1117 x 10^8 mi/min
<span>Speed of light in vacuum = 11.17 x 10^6 mi/min</span>
Answer:
95.50
Step-by-step explanation:
a constant is a number not attached to a variable
in this case the variables are c and w
95.50 is the only one without a variable
