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Anettt [7]
3 years ago
11

Which beat describes how to solve the equation below? 35x=88 A. Divide both sides by 88 B. Multiply both sides by 35 C. Divide b

oth sides by 35 D. Multiply both sides by 88
Mathematics
1 answer:
Alex Ar [27]3 years ago
7 0
The correct answer is C. Divide both sides by 35
I'll show you
35x=88
35x/35 = 88/35
x=2.5
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What is the cube of the square of the second smallest prime number?
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Answer:8

Step-by-step explanation:

The smallest prime is 2

cube of 2 is equal to 8

2*2*2=8

3 0
3 years ago
5<br> Solve for z in the literal equation - (z +11) = y.<br> 7<br> Z=
Vsevolod [243]

Answer:

z= -55 / 5-y

the line is a divided by sign you put 55 on top and the 5-y on bottom

7 0
3 years ago
7/8 - 1/12 its a math question
kati45 [8]

Answer:

19/24 = 0.791666667

Step-by-step explanation:

7/8 - 1/12

Least common multiple of 8 and 12 is 24. Convert 7/8 and 1/12 to fractions with denominator 24.

21/24 - 2/24

Since 21/24 and 2/24 have the same denominator, subtract them by subtracting their numerators.

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19/24

4 0
2 years ago
Which linear equation represents the graph?
8090 [49]

Answer:

The answer is C. Y= -3x+6

The answer can be found by substitute 0 into x and find the value of y. If the value is same with graph then it is correct.

Thank you and please rate me as brainliest as it will help me to level up

4 0
3 years ago
Determine,in each of the following cases, whether the described system is or not a group. Explain your answers. Determine what i
zheka24 [161]

Answer:

(a) Not a group

(b) Not a group

(c) Abelian group

Step-by-step explanation:

<em>In order for a system <G,*> to be a group, the following must be satisfied </em>

<em> (1) The binary operation is associative, i.e., (a*b)*c = a*(b*c) for all a,b,c in G </em>

<em>(2) There is an identity element, i.e., there is an element e such that a*e = e*a = a for all a in G </em>

<em> (3) For each a in G, there is an inverse, i.e, another element a' in G such that a*a' = a'*a = e (the identity) </em>

<em> </em>

If in addition the operation * is commutative (a*b = b*a for every a,b in G), then the group is said to be Abelian

(a)  

The system <G,*> is not a group since there are no identity.  

To see this, suppose there is an element e such that  

a*e = a

then  

a-e = a which implies e=0

It is easy to see that 0 cannot be an identity.

For example  

2*0 = 2-0 = 2

Whereas

0*2 = 0-2 = -2

So 2*0 is not equal to 0*2

(b)

The system <G,*> is not a group either.

If A is a matrix 2x2 and the determinant of A det(A)=0, then the inverse of A does not exist.

(c)

The table of the operation G is showed in the attachment.

It is evident that this system is isomorphic under the identity map, to the cyclic group

\mathbb{Z}_{5}

the system formed by the subset of Z, {0,1,2,3,4} with the operation of addition module 5, which is an Abelian cyclic group

We conclude that the system <G,*> is Abelian.

Attachment: Table for the operation * in (c)

4 0
3 years ago
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