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yan [13]
3 years ago
6

5a + 7b - 4 ( 3a + 6) = Hellpppp

Mathematics
1 answer:
Ivanshal [37]3 years ago
5 0
The answer is -7a+7b-24
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Can someone pls help me / alguien me puede ayudar
user100 [1]

Answer:

The simplified expression is:

\frac{2}{5}y+\frac{1}{5}x-0.2y-6+\left(-2\right)=0.2y+0.2x-8

Step-by-step explanation:

Given the expression

\frac{2}{5}y+\frac{1}{5}x-0.2y-6+\left(-2\right)

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

=\frac{2}{5}y+\frac{1}{5}x-0.2y-6-2

\mathrm{Group\:like\:terms}

=\frac{2}{5}y-0.2y+\frac{1}{5}x-6-2

Add similar elements

=0.2y+\frac{1}{5}x-6-2

=0.2y+\frac{x}{5}-6-2

=0.2y+\frac{x}{5}-8

=0.2y+0.2x-8

Thus, the simplified expression is:

\frac{2}{5}y+\frac{1}{5}x-0.2y-6+\left(-2\right)=0.2y+0.2x-8

6 0
3 years ago
What number round to 200.000 when rounded to the nearest hundred thousand? Choose all that apply
Anuta_ua [19.1K]

Answer:

Is there multiple choice to this question?

anyway the answer maybe is: 0

7 0
2 years ago
1. what would the effect have been on the calculated formula weight ([9] above) of your unknown as compared to the true formula
kramer

If the solution is blue-green, this indicates that some copper is still present in the solution and that not all of it has precipitated. Expect it to be too low because you will have less mass.

With very few exceptions, all copper(I) (cuprous) compounds are diamagnetic and colorless. Cu2O, Cu2Cl2, and cuprous sulfide are a few of the significant commercial compounds of copper(I) (Cu2S).

The molar mass of the element copper is determined by looking at its average atomic mass, which is 63.55 AMU on the periodic table. Since it is also our molar mass, we will now put it in a different unit: grams over moles (63.55 gmol). That is copper's molar mass.

If the solution is blue-green, there is still copper in the solution and not all of it has precipitated. Because you will have less bulk, anticipate it to be too low.

To know more about copper, refer to this link:

brainly.com/question/1543891

#SPJ4

3 0
1 year ago
What is the product of 1 1/2 and -1 1/4?
Savatey [412]

positive number times negative number is negative number "(+)(-) = (-)".

1\dfrac{1}{2}\cdot\left(-1\dfrac{1}{4}\right)=-\left(1\dfrac{1}{2}\cdot1\dfrac{1}{4}\right)

we change the mixed numbers to the improper fractions

=-\left(\dfrac{1\cdot2+1}{2}\cdot\dfrac{1\cdot4+1}{4}\right)=-\left(\dfrac{3}{2}\cdot\dfrac{5}{4}\right)=-\dfrac{3\cdot5}{2\cdot4}=-\dfrac{15}{8}=-1\dfrac{7}{8}

6 0
3 years ago
Question
mixer [17]

The intervals are given as follows:

  • In range notation: [-282, 20,320].
  • In set-builder notation: {x|x ∈ ℝ, -282 <= x <= 20,320}

<h3>What is the range of elements notation for interval?</h3>

The range of elements notation for interval is given by:

[a,b].

In which:

  • a is the smallest value.
  • b is the greatest value.

In this problem these values are given by:

a = -282, b = 20,320.

Hence the interval in range notation is given by:

[-282, 20,320].

<h3>How to write the interval in set-builder notation?</h3>

The same interval can be written as follows, using set-builder notation?

{x|x ∈ ℝ, a <= x <= b}

Hence, for the situation described in this problem, the set-builder notation for the values is:

{x|x ∈ ℝ, -282 <= x <= 20,320}

More can be learned about notation of intervals at brainly.com/question/27896097

#SPJ1

5 0
2 years ago
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