1. Refer to Expression 1 and Expression 2.
1 answer:
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Answer:
Step-by-step explanation:
for two matrices A, B to be Similar, then A = SBS⁻¹
A=SBS−1⟹trace(A)=trace((SB)(S−1))=trace((S−1)(SB))=trace((SS−1)B)=trace(B)
Answer:
Hyperbola
Step-by-step explanation:
Lets write variables in square form using completing the square method
LEts group x and y terms
y^2 terms should be positive always, so we pull out negative sign from y^2
We have negative sign in the middle. so we will get equation in the form of
If we have negative sign in the middle then it is an hyperbola