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STatiana [176]
3 years ago
10

Ten students compared the amount (in dollars) they spent on books each week. The box plot shows the results. The median amount t

hey spent each week is ____ ($20,$30,$40,$50) . The difference of the first and third quartiles of the data set is ____ ($15,$30,$45,$60).

Mathematics
2 answers:
belka [17]3 years ago
7 0
The median is 50.
The first quartile is 20, the third is 65, the difference is 45.
RUDIKE [14]3 years ago
7 0

The box plot contains a box and 5 points:

  1. 1st point is the left endpoint (the smallest number);
  2. 5th point is the right endpoint (the greatest number);
  3. 2nd point is Q_1 - first quartile;
  4. 3rd point is Q_2 - second quartile = median;
  5. 4th point is Q_3 - third quartile.

Then the median is $50,  and Q_3-Q_1=\$65-\$20=\$45.

Answer: $50; $45.

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netineya [11]

Oscar played games vs number of points he scored is, C) positive, linear association.

Step-by-step explanation:

  • no association is when points Oscar graph will remain between 8to10.
  • number of games he scored his points remain the same which is mean.
  • non linear is only when there is no straight line passing.
  • Linear is either exponential or polynomial.
  • Positive as the game increase he scoring abilities increases.
  • Negative as the game increases his scoring decreases.
  • Negative x axis will have more number of points.
  • Negative y axis will high to low of the graph.
  • Linear lines are best way to predict a data doesn't work will all data.

8 0
3 years ago
jake can carry 6 1/4 pounds of wood in from the barn. his father can carry 1 5/7 times as much as jake. how many pounds can jake
Andrej [43]
Dear Jat2324, Jake's father can carry 10 5/7 pounds of wood.
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7 0
3 years ago
Rewrite 3√5^2 with a rational exponent.
Law Incorporation [45]

Answer:

C. 5 2/3

Step-by-step explanation:

3 0
3 years ago
A null hypothesis is that the mean nose lengths of men and women are the same. The alternative hypothesis is that men have a lon
algol [13]

Answer:

b. There is not enough evidence to say that the populations of men and women have different mean nose lengths.

See explanation below.

Step-by-step explanation:

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different (men have longer mean nose length than women), the system of hypothesis would be:

Null hypothesis:\mu_{men} \leq \mu_{women}

Alternative hypothesis:\mu_{men} > \mu_{women}

Assuming that we know the population deviations for each group, for this case is better apply a z test to compare means, and the statistic is given by:

z=\frac{\bar X_{men}-\bar X_{women}}{\sqrt{\frac{\sigma^2_{men}}{n_{men}}+\frac{\sigma^2_{women}}{n_{women}}}} (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Let's assume that the calculated statistic is z_{calc}

Since is a right tailed test test the p value would be:

p_v =P(Z>z_{calc})=0.225

And we know that the p value is 0.225. If we select a significance level for example 0.05 or 0.1 we see that p_v >\alpha

And on this case we have enough evidence to FAIl to reject the null hypothesis that the means are equal. So then the best conclusion would be:

b. There is not enough evidence to say that the populations of men and women have different mean nose lengths.

8 0
3 years ago
Can someone help me with this question
valentina_108 [34]
Answer:
B

————-

I’m not 100% sure though
3 0
3 years ago
Read 2 more answers
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