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Hitman42 [59]
3 years ago
10

I HAVE 5 MINUTES PLEASE HELP ! ( slope )

Mathematics
2 answers:
Natali [406]3 years ago
7 0

Answer: Graph (4,3) like it says, then go up 1 and right 2. That would be (6,4). You can also go down 1 and left 2. That would be (2,3)

Step-by-step explanation: Your welcome :)

astraxan [27]3 years ago
5 0

Answer:

1/2x+b=y

1/2*4+b=3

2+b=3

b=1

1/2x+1=y

Step-by-step explanation:

You might be interested in
Number d I need help with
Natasha2012 [34]

Answer:

15 5/9 °C

Step-by-step explanation:

Put 60 where F is in the equation and do the arithmetic.

... C = (5/9)(60 -32) = (5/9)(28) = 140/9

... C = (135 +5)/9 = 15 5/9

8 0
3 years ago
17d+32a=176 what is d?
Vlad [161]
Minus 32a from both sides
17d=176-32a
divide both sides by 17
d=\frac{176-32a}{17}
4 0
3 years ago
Which of the following is not a congruence theorem or postulate A. ASA B. SSS C. SAS D. AAA
natka813 [3]

Answer:

D. AAA is not a congruence postulate

Step-by-step explanation:

6 0
2 years ago
Please help me with #7
Dominik [7]

Step-by-step answer:

This is a regular heptagon, means it has 7 <em>congruent</em> sides and 7 <em>congruent </em>vertex angles.

To work with polygons, there is a very important piece of information that you must know to solve the majority of related problems.

This is:

sum of exterior angles of polygons = 360 degrees.

If you don't remember the 360 degrees, think of the sum of exterior angles of an equilateral triangle, which is 3*(180-60)=3*120=360!  It works!

For a regular heptagon, c = 360/7=51.43 degrees approx.

This means that each vertex angle measures

vertex angle = 180-c

So since 2d+the vertex angle = 360, we have

2d+(180-c)=360

solve for d:

2d=360-(180-c)=180+c

d=(180+c)/2=90+c/2=115.71 degrees. (approx.)

8 0
3 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
2 years ago
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