289 196 248 379 319 276 198 349
(in order) 196, 198, 248, 276, 289, 319, 349, 379 there are eight numbers.
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196, 198, 248, 276
since the median is between 198 and 248, we must add both numbers together and divide them by two:
(198 + 248) ÷ 2
= 446/2
<h2>
= 223 (first quartile)</h2>
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289, 319, 349, 379
since the median is between 319 and 349, we must add both numbers together and divide them by two:
(319 + 349) ÷ 2
= 668/2
<h2>
= 334 (third quartile)</h2>
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Interquartile range:
<h2>
IQR: 334 - 223 = 111 </h2>
<em>I double-checked my answers btw</em>
Bx + x^2 + 10 that is the answer i hope this helps you
Answer:
A 24
Step-by-step explanation:
Assuming this is a right triangle, we can use the Pythagorean theorem
a^2+ b^2 = c^2
a^2 + 7^2 = 25^2
a^2 +49= 625
Subtract 49 from each side
a^2 +49-49 = 625-29
a^2 = 576
Take the square root of each side
sqrt(a^2) = sqrt(576)
a = 24
Simple. 4x19 = 76+2 = 78-5 = 73
