Help please i dont know what to do!

Each grape at the supermarket weighs 5 grams. If Eric buys a bag of grapes that weighs 50 grams, how many grapes did he buy?

Usimov [2.4K]

Answer:

10 grapes

Step-by-step explanation:

50 divided by 5 is 10

7 0

3 years ago

According to an article in Newsweek, the natural ratio of girls to boys is 100:105. In China, the birth ratio is 100:114 (46.7%

mojhsa [17]

Answer:

$z=\frac{0.42 -0.467}{\sqrt{\frac{0.467(1-0.467)}{150}}}=-1.154$

$p_v =2*P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of girls born is not significantly different from 0.467

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=63 represent the number of girls born

$\hat p=\frac{63}{150}=0.42$ estimated proportion of girls born

$p_o=0.467$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion if girls is 0.467.:

Null hypothesis: $p=0.467$

Alternative hypothesis: $p \neq 0.467$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.42 -0.467}{\sqrt{\frac{0.467(1-0.467)}{150}}}=-1.154$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of girls born is not significantly different from 0.467

3 0

3 years ago

A polling company reported that % of surveyed adults said that Complete parts (a) through (d) below.

SOVA2 [1]

Answer:

a) 376.66

b) Option 2: No, the result from part (a) could not be the actual number of adults who said that rising gas prices are "quite annoying" because a count of people must result in a whole.

c) 377

d) 40.77%

Step-by-step explanation:

a) 37% of 1018 is;

37/100 × 1018 = 376.66

b) Thus, the result in a above is not a whole number. Thus;

No, the result from part (a) could not be the actual number of adults who said that rising gas prices are "quite annoying" because a count of people must result in a whole.

c) from a above a, we got a value of 376.66.

Now the actual number would be preferably an integer. Thus, actual number is approximately 377.

d) percentage of respondents said that cellular phones are not at all harmful = 415/1018 × 100% = 40.77%

8 0

3 years ago

Solve for y: 2(3y+5)=3(5y+1/3)

DerKrebs [107]

.93 would have to be the answer because you do the regular calculations, then you divide to find y.

7 0

3 years ago

Read 2 more answers

What’s the correct answer

astra-53 [7]

I think the correct answer is A. 1

7 0

3 years ago