Answer: The two integers are 8 and 9.
Step-by-step explanation: Let n represent the number.
n^2 + (n + 1)^2 = 145
By foiling, this can be rearranged to:
n^2 + n^2 + 2n + 1 = 145
Subtract 145 from both sides:
2n^2 + 2n - 144 = 0
Divide both sides by 2:
n^2 + n - 72 = 0
Factor the polynomial:
(n + 9)(n - 8) = 0
Solve for n:
n = -9, n = 8
Since they need to be consecutive, make the 9 positive. It will be positive either way because it is being squared.
Now, n = 9 and n = 8.
These are your two integers. Hope this helps!
Hopefully this is what you are looking for.
5(q^2-r)+8(3q+2r)
Does this look like what you are currently doing?
5q^2-5r+24q+16r
5q^2+24q+11r
Answer:
2/9, 11/18, 2/3, 5/6
Step-by-step explanation:
2/3= 12/18 2/9= 4/18 5/6= 15/18 11/18= 11/18
covert all into least common denominator in this case 18 then order
Hope this helps!
