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cricket20 [7]
3 years ago
12

Write an algebraic expression for “5 times the difference of q squared and r plus 8 times the sum of 3q and 2r”. Then simplify t

he expression and indicate the properties used.
Mathematics
1 answer:
Semmy [17]3 years ago
4 0
Hopefully this is what you are looking for.

5(q^2-r)+8(3q+2r) 
Does this look like what you are currently doing?

5q^2-5r+24q+16r
5q^2+24q+11r

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Assume the annual interest rate is 6%. Calculate the value of an investment that pays $100 every two years, starting two
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2 years ago
a spherical snowball is melting in such a manner that its radius is changing at a constant rate, decreasing from 27 cm to 17 cm
Phoenix [80]

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3.30=90

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2 years ago
Show tan(???? − ????) = tan(????)−tan(????) / 1+tan(????) tan(????)<br> .
anyanavicka [17]

Answer:

See the proof below

Step-by-step explanation:

For this case we need to proof the following identity:

tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}

We need to begin with the definition of tangent:

tan (x) =\frac{sin(x)}{cos(x)}

So we can replace into our formula and we got:

tan(x-y) = \frac{sin(x-y)}{cos(x-y)}   (1)

We have the following identities useful for this case:

sin(a-b) = sin(a) cos(b) - sin(b) cos(a)

cos(a-b) = cos(a) cos(b) + sin (a) sin(b)

If we apply the identities into our equation (1) we got:

tan(x-y) = \frac{sin(x) cos(y) - sin(y) cos(x)}{sin(x) sin(y) + cos(x) cos(y)}   (2)

Now we can divide the numerator and denominato from expression (2) by \frac{1}{cos(x) cos(y)} and we got this:

tan(x-y) = \frac{\frac{sin(x) cos(y)}{cos(x) cos(y)} - \frac{sin(y) cos(x)}{cos(x) cos(y)}}{\frac{sin(x) sin(y)}{cos(x) cos(y)} +\frac{cos(x) cos(y)}{cos(x) cos(y)}}

And simplifying we got:

tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}

And this identity is satisfied for all:

(x-y) \neq \frac{\pi}{2} +n\pi

8 0
3 years ago
What is ____ divided 12 = 3? What is the answer to the blank?
Ksivusya [100]
x:12=3\to x=3\times12=36\\\\Answer:\\36:12=3
5 0
3 years ago
Read 2 more answers
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