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Tasya [4]
3 years ago
12

Select the correct answer.

Mathematics
1 answer:
ELEN [110]3 years ago
5 0

Answer:

D

Step-by-step explanation:

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HALP. First answer brainliest
Rom4ik [11]

Answer:

5.68

Step-by-step explanation:

it is 5.67812

I just rounded the answer like is says to

8 0
3 years ago
Read 2 more answers
A six-sided number cube is rolled twice.
Marina CMI [18]

Answer: A and D

Step-by-step explanation:

Dependent events mean that one event depends on the outcome of the previous event.

A) If the first roll is a 3, and we want to sum more than 7 with the second roll, then the possible outcomes 5 and 6. Now if the first roll is 4, then the possible outcomes for the second event will be 4, 5 and 6. So you can see how the outcome space of the second event changes depending on the first event, so the events are dependent.

B) Here we do not have dependence, each event only depends on it's own outcome.

C) Again, both events only depend on it's own outcome, so the events are not dependent.

D) This is similar as the case for A, these events are dependent because is not the same if the outcome of the first event is 3, than if the outcome is 5 (the outcome needed for the second roll changes depending on the outcome of the first event)

E) Same as B and C, the events are independent.

4 0
3 years ago
What num com between 4 and 6?
damaskus [11]

Answer:

5

Step-by-step explanation:

1,2,3,4,5,6

7 0
2 years ago
Read 2 more answers
Find the volume of the solid formed by revolving the region bounded by LaTeX: y = \sqrt{x} y = x and the lines LaTeX: y = 1 y =
Strike441 [17]

Answer:

The volume is:

\displaystyle\frac{37\pi}{10}

Step-by-step explanation:

See the sketch of the region in the attached graph.

We set the integral using washer method:

\displaystyle\int_a^b\pi r^2dx

Notice here the radius of the washer is the difference of the given curves:

x-\sqrt{x}

So the integral becomes:

\displaystyle\int_1^4\pi(x-\sqrt{x})^2dx

We solve it:

Factor \pi out and distribute the exponent (you can use FOIL):

\displaystyle\pi\int_1^4x^2-2x\sqrt{x}+x\,dx

Notice: x\sqrt{x}=x\cdot x^{1/2}=x^{3/2}

So the integral becomes:

\displaystyle\pi\int_1^4x^2-2x^{3/2}+x\,dx

Then using the basic rule to evaluate the integral:

\displaystyle\pi\left[\frac{x^3}{3}-\frac{2x^{5/2}}{5/2}+\frac{x^2}{2}\right|_1^4

Simplifying a bit:

\displaystyle\pi\left[\frac{x^3}{3}-\frac{4x^{5/2}}{5}+\frac{x^2}{2}\right|_1^4

Then plugging the limits of the integral:

\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(4)^{5/2}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]

Taking the root (rational exponents):

\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(2)^{5}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]

Then doing those arithmetic computations we get:

\displaystyle\frac{37\pi}{10}

6 0
3 years ago
Help Help! Now help! ASAP!I’ll make you brainly now please
hammer [34]

Answer:

re08uwahrewrai098nyryvrhheuaviufvsdsavad <<< Don't do this please

42.3 meters

3 0
3 years ago
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