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gtnhenbr [62]
2 years ago
8

Mateo is culturing bacteria that have a growth rate of 5.3% per hour. If the current population is 38,762 bacteria, how many bac

teria will there be in 20 hours?If necessary, round your answer to the nearest whole number.
Mathematics
1 answer:
Taya2010 [7]2 years ago
8 0

..Given:

\begin{gathered} a=38762 \\ r=5.3\%=\frac{5.3}{100}=0.053 \\ t=20 \end{gathered}

To Determine: The number of bacteria after 20 hours

Using the future value formula for growth rate

\begin{gathered} P_a=P_c(1+r)^t \\ P_a=(Bacteria,final,population) \\ P_c(Bacteria,current,population)=38762 \\ r(rate)=0.053,t(time,in,hour)=20 \end{gathered}

Therefore

\begin{gathered} P_a=38762(1+0.053)^{20} \\ P_a=38762(1.053)^{20} \\ P_a=38762(2.809101) \\ P_a=108886.39 \\ P_a\approx108886 \end{gathered}

Hence, population of bacteria in 20 hours is 108,886

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Step-by-step explanation:

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4 years ago
Determine the number of possible triangles, ABC, that can be formed given A = 30°, a = 7, and b = 18.
zzz [600]

Answer:

none

Step-by-step explanation:

We are given a triangle ABC with ∠A = 30°, sides a = 4 and b = 10.

According to the 'Law of Sines- Ambiguous Case', we have,

If a < b×sinA, then no triangle is possible.

If a = b×sinA, only one triangle is possible

If a > b×sinA, two triangles are possible.

So, we have,

b×sinA = 10 × sin30 = 10 × 0.5 = 5.

Now, as

4 = a < bsinA = 5.

We get, according to the rule, no triangle is possible.

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2 years ago
18 minutes left hwhsusbe
Pepsi [2]

Answer:

so its D

Step-by-step explanation:

a is wrong becuase it does have 6

b is wrong becuase you make into 6 triangles

c is wrong becuase it does add up to 180 degrees

6 0
3 years ago
In August, 85% of the middle school students voted in a school election. The number of students who voted was 544. How many stud
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Step-by-step explanation:

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3 years ago
Evaluate the integral e^xy w region d xy=1, xy=4, x/y=1, x/y=2
LUCKY_DIMON [66]
Make a change of coordinates:

u(x,y)=xy
v(x,y)=\dfrac xy

The Jacobian for this transformation is

\mathbf J=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial v}{\partial x}\\\\\dfrac{\partial u}{\partial y}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}y&x\\\\\dfrac1y&-\dfrac x{y^2}\end{bmatrix}

and has a determinant of

\det\mathbf J=-\dfrac{2x}y

Note that we need to use the Jacobian in the other direction; that is, we've computed

\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}

but we need the Jacobian determinant for the reverse transformation (from (x,y) to (u,v). To do this, notice that

\dfrac{\partial(x,y)}{\partial(u,v)}=\dfrac1{\dfrac{\partial(u,v)}{\partial(x,y)}}=\dfrac1{\mathbf J}

we need to take the reciprocal of the Jacobian above.

The integral then changes to

\displaystyle\iint_{\mathcal W_{(x,y)}}e^{xy}\,\mathrm dx\,\mathrm dy=\iint_{\mathcal W_{(u,v)}}\dfrac{e^u}{|\det\mathbf J|}\,\mathrm du\,\mathrm dv
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8 0
3 years ago
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