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SOVA2 [1]
3 years ago
8

Plz help me!!!!!!!!! Which expression is represented by the model? A. B. C. D.

Mathematics
2 answers:
Finger [1]3 years ago
5 0
D, since X has only one box and is negative.
Shalnov [3]3 years ago
4 0

Answer:

Im pretty sure its D i had a problem like this as well.

Step-by-step explanation:

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I've got pizza you can have a slice if you come on remind <3
Sidana [21]

Answer:

5<3

Step-by-step explanation:

8-3= 5

7 0
3 years ago
Help please now
Allisa [31]

Answer:

Part A

30

44

26

Part B

176

Step-by-step explanation:

Total: 65+110+75 = 250

P(O) = 75/250 × 100 = 30%

P(A) = 110/250 × 100 = 44%

P(K) = 65/250 × 100 = 26%

Apple juice:

44% of 400

44/100 × 400

176

5 0
4 years ago
PLEASE HELP :((((((((((((((
natita [175]

Answer:c

Step-by-step explanation:

4 0
4 years ago
Find the mean absolute deviation
pantera1 [17]
First find the mean (sum divided by number of values)
4+5+8+10+15=42
42/5=8.4
Then find the difference between each of the numbers and the mean.
4.4, 3.4, 0.4, 1.6, 6.6
Then find the mean of those values.
4.4+3.4+0.4+1.6+6.6=16.4
16.4/5=3.28
Final answer: 3.28
6 0
3 years ago
Read 2 more answers
A manufacturer has determined that a model of its washing machine has an expected life that is Exponential with a mean of four y
krek1111 [17]

Complete question:

A manufacturer has determined that a model of its washing machine has an expected life that is Exponential with a mean of four years to failure and irrelevant board burn-in period. He wants to testthe system and complete data collection. Find the probability that one of these washing machines will have a life that ends: (Note you can find the reliability of the washing machine life)

a) After an initial four years of washing machine service

b) Before four years of washing machine service are completed

c) Not before six years of washing machine service.

Answer:

a) 0.3679

b) 0.6321

c) 0.2231

Step-by-step explanation:

Given:

Mean, u= 4

/\ = 1/u

= 1/4 = 0.25

The cummulative distribution function, will be:

For x≥0,

F(x) = 1 - e^-^0^.^2^5^X

P(x

a) After an intial four years:

P(x>4) = 1-(1-e^-^0^.^2^5^*^4^.^0)

P(x>4) = 0.3679

b) Before four years:

P(x

P(x<4) = 0.6321

c) Not before 6 years:

P(x>6) = 1-(1-e^-^0^.^2^5^*^4^.^0)

P(x>6) = 0.2231

5 0
3 years ago
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