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dimulka [17.4K]
3 years ago
9

Solve the inequality 3x^2 + 10x - 8 < 0​

Mathematics
1 answer:
Ksivusya [100]3 years ago
8 0

Step-by-step explanation:

Given, 3x−2<2x+1

⇒3x−2x<1+2

⇒x<3orx∈(−∞,3)

The lines y=3x−2 and y=2x+1 both will intersect at x=3

Clearly, the dark line shows the solution of 3x−2<2x+1.

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For leaving school to visit Mexico Levant traded 270 American dollars and received 3000 Mexican pesos. When he returned from Mex
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Each peso is 0.052 so each is 52 cents so now you times it by 100 and you will have your anser are divid it :D glad to help you
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Whats the answer for this question?
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-7(2 + n) + 1/3(-9 - 6n)
-14 - 7n -3 - 2n
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Heres another math problem
MrRissso [65]

Answer:

\therefore x=50\°

Step-by-step explanation:

Let the angle between 2x and 150° be = b°

150\°+b\°=180\° [ Forming a linear pair of angles]

Solving for b by subtracting both sides by 150.

150+b-150=180-150

∴ b=30\°

50\°+2x+b\°=180\°\\ [Angle lying on a straight line add up to 180]

Plugging in b=30\°

50+2x+30=180\\2x+80=180

Solving for x by

subtracting both sides by 80.

2x+80-80=180-80\\2x=100

then dividing both sides by 2.

\frac{2x}{2}=\frac{100}{2}\\\\\therefore x=50\°

4 0
3 years ago
Read 2 more answers
This week at HEB, pork chops cost $1.60 per pound. Steve bought 2 1/4 pounds of pork chops. If he paid with a $10 bill, how much
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Answer:

He received $6.40 in change.

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Since he bought 2.25 pounds, you multiply that by 1.6 to get a sum of 3.6. Since he paid with a ten dollar bill, and he only has to pay 3.60, they will give him back 6.40 in change.

Hope this helped :)

6 0
3 years ago
Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. y2
HACTEHA [7]

This question is incomplete, the complete question is;

Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. y2 = 2x, x = 2y; about the y-axis

Answer:

V = π (512/15)

Step-by-step explanation:

Given that;

region of rotation

y² = 2x, x = 2y

Region is rotated about y-axis as shown in the image

for the point of intersection,

y²/2 = 2y

y² - 4y = 0

y(y-4) = 0

∴ y = 0, y = 4

so the region lies in 0 ≤ y ≤ 4

Now cross section area of washer is

A(y) = π(outer radius)² = π(inner radius)²

A(y) = π(2y)² - π(y²/2)²

A(y) = π(4y²) - π(y⁴/4)

A(y) = π(4y² - (y⁴/4))

now volume of the solid of revolution is

V = ⁴∫₀ A(y) dy

V = ⁴∫₀ π(4y² - (y⁴/4))dy

V =  π {4⁴∫₀ y² - 1/4⁴∫₀y⁴ dy }

V = π { 4/3 [y³]₀⁴ - 1/20 [y⁵]₀⁴ }

V = π { 4/3 [4]₀⁴ - 1/20 [4]₀⁴ }

V = π { 4/3 [64]₀⁴ - 1/20 [1024]₀⁴ }

V = π { 256/3 - 1024/20 }

V = π { (5120 - 3072) / 60 }

V = π (512/15)

8 0
3 years ago
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