Please help me to do this sinx+cosx-sin(x-30)+cos(x-30)=√6cos(x-15)

HELP ME I MESSED UP ON MY OTHER QUESTION PLZ I WILL GIVE YOU ALOT OF POINTS

xxTIMURxx [149]

Answer:

10/8 = 5/4x

y=5/4x

hope that answers your question

Step-by-step explanation:

7 0

3 years ago

Which number is irrational? A: √9 B: √8 C: 0.3333 D: 2/3 Answer fast please

Arisa [49]

$\sqrt{8}$ is an irrational number ⇒ answer B

Step-by-step explanation:

Let us explain the meaning of:

A rational number is a number that can be written as a fraction
An irrational number is a number that cannot be expressed as a fraction

Examples:

Rational numbers : 10 , $\frac{2}{5}$ , 0.333

Irrational numbers : π , √8 , ∛25 , (2 + √5) , $\frac{\sqrt{7}}{3}$

∵ $\sqrt{9}=3$

∵ 3 is a rational number

∴ $\sqrt{9}$ is a rational number

∵ $\sqrt{8}$

∵ There is no square root of 8

∴ $\sqrt{8}$ is an irrational number

∵ 0.3333 can be expressed as $\frac{3333}{10000}$

∴ 0.3333 is a rational number

∵ $\frac{2}{3}$ is a fraction

∵ All fractions are rational numbers

∴ $\frac{2}{3}$ is a rational number

$\sqrt{8}$ is an irrational number

Learn more:

You can learn more about real numbers in brainly.com/question/4853862

#LearnwithBrainly

5 0

3 years ago

. Scalene triangle SCL with angle bisector CM

Firdavs [7]

32 but make sure it’s emedicpend PAS

3 0

3 years ago

Circle O has a center at (-2, 10) and a

allsm [11]

Answer:

B

Step-by-step explanation:

If the point lies on the circle, the distance of the point to the center would be equivalent to the circle's radius since radius is defined as the distance from the center to any point of the circle.

Since length of a radius is half of a diameter,

radius= diameter ÷2

radius= 12 ÷2

radius= 6 units

Let's find the length between each points to see which is equal to 6 units, using the distance formula below.

$distance = \sqrt{(y1 - y2)^{2} + {(x1 - x2)}^{2} }$

A. Distance between 2 points

$= \sqrt{ {(10 + 5)}^{2} + ( - 2 + 6)^{2} } \\ = \sqrt{15 ^{2} + {4}^{2}} \\ = \sqrt{241} \\ = 15.524 \: units$

(to 5 s.f.)

Since the distance is greater than 6 units, point A lies outside the circle.

B. Distance between 2 points

$= \sqrt{ {(10 - 4)}^{2} + ( - 2 + 2)^{2} } \\ = \sqrt{ {6}^{2} } \\ = 6 \: units$

Since the distance of B from the center is 6 units, point B lies on Circle O.

Let's check the other 2 points:

C. Distance between 2 points

$= \sqrt{ {(10 - 4)}^{2} + {( - 2 - 6)}^{2} } \\ = \sqrt{ {6}^{2} + ( - 8)^{2} } \\ = \sqrt{100} \\ = 10 \: units$

Since the distance of point C from the center is greater than 6 units, point C lies outside the circle.

D. Distance between 2 points

$= \sqrt{ {(10 - 8)}^{2} + {( - 2 - 8)}^{2} } \\ = \sqrt{2^{2} + ( - 10)^{2} } \\ = \sqrt{104} \\ = 10.198 \: units$

(to 5 s.f.)

Point D also lies outside Circle O.

8 0

4 years ago

Andrew ran 4.5 miles in 32 minutes.

PtichkaEL [24]

Answer:

C

Step-by-step explanation:

4.5/32=x/54

5 0

4 years ago

Please help me to do thissinx+cosx-sin(x-30)+cos(x-30)=√6cos(x-15)​

Please help me to do thissinx+cosx-sin(x-30)+cos(x-30)=√6cos(x-15)