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3 years ago

15

This student incorrectly simplified this expression.

1 answer:

Lady_Fox [76]3 years ago

8 0

Answer:

/

dont subtract 3 from -7m so it would be -7m + 3

7m

/

= m = 3

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You open a book to two facing pages. The product of the two pages is 600. Find the page numbers.

Ivan

To find this, use an equation with x to represent the smaller page number as your variable. set up the equation x(x+1) = 600. distribute the x to get x^2 + x = 600. subtract 600 from both sides so you have x^2 + x - 600 = 0. factor to get (x+24)*(x+25) = 0. so the two pages are 24 and 25

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3 years ago

Simplify each expression.<br>1. 46° =

Viktor [21]

Answer:

Step-by-step explanation

-7 degrees Celsius

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3 years ago

The Carter family just left the local pet store with Rex, their new family dog. The pet store owner told the Carter family that

Korolek [52]

Answer:

A.)

In 2 months, Rex is 6 pounds and in 8 months he's 9lbs (from 2 to 8 is 6 months). So I inferred that to get to 9lbs from 6lbs is to go 0.5 pounds more each month.

B.)

2 = 6

3 = 6.5

4 = 7

5 = 7.5

6 = 8

7 = 8.5

8 = 9

C.) I don't think I can create a linear model here. So I don't think its nessesary.

D.)

If Rex were to grow over the expected 6 months, it would be 45.

5 0

3 years ago

a hose fills a hot tub at a rate of 4.97 gallons per minute. How many hours will it take to fill a 336-gallon hot tub?

Eddi Din [679]

Answer:

1.12675hours approximately

Step-by-step explanation:

If the tub was 4.97 gallons it would take 1 minute Right?

To find the the time required to fill the tub divide volume of tub by the rate of hose. We have 336/4.97=67.605minutes

Divide by 60` 67.605/60=1.12675hours approximately

6 0

3 years ago

Bezzdna [24]

Answer:

$y=-\dfrac{9}{40}x^2+\dfrac{441}{40}\\ \\y=-\dfrac{9}{160}x^2+\dfrac{1,521}{160}$

Step-by-step explanation:

If a parabola has its vertex on the y-axis, then its equation is

$y=ax^2+b$

This parabola passes through the point R(3,9), then

$9=a\cdot 3^2+b\\ \\9=9a+b$

The area of the right triangle PQR is

$A_{PQR}=\dfrac{1}{2}\cdot PQ\cdot QR$

Find PQ and QR, if $P(x_1,0),\ Q(3,0),\ R(3,9):$

$PQ=\sqrt{(x_1-3)^2+(0-0)^2}=|x_1-3|\\\\QR=\sqrt{(3-3)^2+(0-9)^2}=9$

Now,

$40.5=\dfrac{1}{2}\cdot |x_1-3|\cdot 9\\ \\90=9|x_1-3|\\ \\|x_1-3|=10\\ \\x_1-3=10\ \text{or}\ x_1-3=-10\\ \\x_1=13\ \text{or }x_1=-7$

We get two possible points $P_1(-7,0)$ and $P_2(13,0).$

For point $P_1:\\$

$0=a\cdot (-7)^2+b\\ \\49a+b=0$

So,

$b=-49a\\ \\9=9a-49a\\ \\-40a=9\\ \\a=-\dfrac{9}{40}\\ \\b=\dfrac{441}{40}\\ \\y=-\dfrac{9}{40}x^2+\dfrac{441}{40}$

For point $P_2:\\$

$0=a\cdot (13)^2+b\\ \\169a+b=0$

So,

$b=-169a\\ \\9=9a-169a\\ \\-160a=9\\ \\a=-\dfrac{9}{160}\\ \\b=\dfrac{1,521}{160}\\ \\y=-\dfrac{9}{160}x^2+\dfrac{1,521}{160}$

5 0

3 years ago