The perimeter of a rectangle is 208 inches. The ratio

Mathematics

1 answer:

bearhunter [10]3 years ago

6 0

Answer:

65 in and 39 in respectively

Step-by-step explanation:

Let r be the common ratio; when we multiply both L and R by this common ratio, we'll get the actual length and actual width of the rectangle, Recalling that the formula for the perimeter of a rectangle is P = 2L + 2R, we get:

2(5r) + 2(3r) = 16r = 208 in

Then r = 208/16 = 13

Thus, the actual length is 5(13 in) and the actual width is 3(13 in.),

or 65 in and 39 in respectively.

As a check, calculate 65 in / 39 in; this comes out to 5:3, as required.

Then

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A large washer has an outer radius of 10mm and a hole with a diameter of 14mm. What is the area of the top surface of the washer

choli [55]

<h2>Answer:</h2>

The area of the top surface of the washer is: 160.14 square mm.

<h2>Step-by-step explanation:</h2>

The top of the surface is in the shape of a annulus with a outer radius of 10 mm and a inner radius of 7 mm ( since the diameter of the hole is: 14 mm and we know that the radius is half of the diameter)

Now, we know that the area of the annulus region is given by:

$Area=\pi (R^2-r^2)$

where R is the outer radius and r is the inner radius.

Here we have:

$R=10\ mm\\\\and\\\\r=7\ mm$

Hence, we have:

$Area\ of\ top\ surface=\pi (10^2-7^2)\\\\i.e.\\\\Area\ of\ top\ surface=\pi (100-49)\\\\i.e.\\\\Area\ of\ top\ surface=\pi\cdot 51\\\\i.e.\\\\Area\ of\ top\ surface=160.14\ mm^2$