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maks197457 [2]
3 years ago
10

I need help asap on number nine. it would be much appreciated. only number 9​

Mathematics
1 answer:
klemol [59]3 years ago
7 0

Answer:

18

Step-by-step explanation:

they are vertical angles so they are equal

6y+40=10y-32

6y+40+32=10y-32+32

6y+72=10y

6y-6y+72=10y-6y

72=4y

72/4=4y/4

18=y

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Ming is mowing a lawn that is 12 feet wide and 25 feet long.
leva [86]

Answer:

300!

Step-by-step explanation:

Because square feet is area and area is length (25) and width (12)

5 0
3 years ago
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Mary has 12 video games. She purchases five new video games each month as part of a video game club.
Oxana [17]

Answer:

The answer to your question is:  V = 12 + 5n

Step-by-step explanation:

Data

Video games right now = 12

She purchases 5 video games each month

Equation = ?

# of video games in n month = V

Process

           - Consider the initial amount of video games

                                   V = 12

           - Now, consider the number of video games the buys each month and the months

                                 5n

           - Finally, join both terms

                                  V = 12 + 5n

8 0
4 years ago
Integrate this two questions ​
tankabanditka [31]

Simplify the integrands by polynomial division.

\dfrac{t^2}{1 - 3t} = -\dfrac19 \left(3t + 1 - \dfrac1{1 - 3t}\right)

\dfrac t{1 + 4t} = \dfrac14 \left(1 - \dfrac1{1 + 4t}\right)

Now computing the integrals is trivial.

5.

\displaystyle \int \frac{t^2}{1 - 3t} \, dt = -\frac19 \int \left(3t + 1 - \frac1{1-3t}\right) \, dt \\\\ = -\frac19 \left(\frac32 t^2 + t + \frac13 \ln|1 - 3t|\right) + C \\\\ = \boxed{-\frac{t^2}6 - \frac t9 - \frac{\ln|1-3t|}{27} + C}

where we use the power rule,

\displaystyle \int x^n \, dx = \frac{x^{n+1}}{n+1} + C ~~~~ (n\neq-1)

and a substitution to integrate the last term,

\displaystyle \int \frac{dt}{1-3t} = -\frac13 \int \frac{du}u \\\\ = -\frac13 \ln|u| + C \\\\ = -\frac13 \ln|1-3t| + C ~~~ (u=1-3t \text{ and } du = -3\,dt)

8.

\displaystyle \int \frac t{1+4t} \, dt = \frac14 \int \left(1 - \frac1{1+4t}\right) \, dt \\\\ = \frac14 \left(t - \frac14 \ln|1 + 4t|\right) + C \\\\ = \boxed{\frac t4 - \frac{\ln|1+4t|}{16} + C}

using the same approach as above.

5 0
2 years ago
If these two shapes are<br> similar, find X
ELEN [110]

Answer:

4

Step-by-step explanation:

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x = 4

4 0
3 years ago
Which one is it A B C or D
Arisa [49]
B. Hoped this helped!!
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