Factor completely 4x5 − 20x4 − 36x3.

Mathematics

1 answer:

lakkis [162]3 years ago

8 0

Answer:

the 2nd one is the answer :)

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: John wants to move from point A to point B. To avoid the pond, he must walk 36 m south and 49 m east. However, he wants to go

just olya [345]

Answer:

60.80

Step-by-step explanation:

6 0

3 years ago

ABCD is a parallelogram and this figure is NOT drawn to scale.

dimulka [17.4K]

The angle does not matter. Think of it as finding the other side to a triangle. Use $a ^{2} +b^2 =c^2$

a=39 (line AB)
b=b (the leg we need to find)
c=89 (line BD)

$39^2 + b^2 = 89^2$
$1521 + b^2 = 7921$
(subtract the 1521 from both sides)
$b^2 = 6400$
(square root both sides)
$\sqrt{(b^2)} = \sqrt{6400} 
$

b = 80
AD=80

7 0

3 years ago

Read 2 more answers

The diagonals of a kite separate the quadrilateral into four congruent triangles

statuscvo [17]

If the sum of two of the sides congruent to each other are greater than that of the sides opposite them, then no. If however the kite forms a rombus ot square, the diagnoles will form four congruent triangles with the base of both being the line of symmetry.
hope this helps :)

6 0

2 years ago

3(9-8x-4x)+8(3x+4)=11

Papessa [141]

3(9 - 8x - 4x) + 8(3x + 4) = 11

3(9 - 12x) + 8(3x + 4) = 11

27 - 36x + 24x + 32 = 11

59 - 12x = 11

-12x = 11 - 59

-12x = -48

x = 4

hope this helps, God bless!

4 0

3 years ago

The volume of the pyramid shown in the figure is cubic centimeters. If the slant height of the pyramid increases by 4 centimeter

Nostrana [21]

Answer:

Part a) The volume of the original pyramid is $15\ cm^{3}$

Part b) The volume of the pyramid increases by $6\ cm^{3}$

Step-by-step explanation:

The complete question is

Part 1) The volume of the pyramid shown in the figure is 9,15,21, or 63 cubic centimeters?. Part 2) If the slant height of the pyramid increases by 4 centimeters and its height increases by 2 centimeters, the volume of the pyramid increases by 6,9,12 or 21 cubic centimeters?

we know that

The volume of the pyramid is equal to

$V=\frac{1}{3}Bh$