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balandron [24]
3 years ago
9

You earn 216 out of a possible 250 point on a report. How much percent is that?

Mathematics
2 answers:
elena-s [515]3 years ago
3 0

Answer:

Letter Grade: B Percentage: 80-89

Step-by-step explanation:

You got 216/250, so divide 216/250 and you get 0.864. This means 216 is 86.4 percent of 250 :)

olganol [36]3 years ago
3 0

Answer:

The answer would be B. 80-89%%

Step-by-step explanation:

Can you mark me brainliest please?

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An element with mass 430 grams decays by 27.4% per minute. How much of the element is remaining after 19 minutes, to the nearest
nadya68 [22]
The equation for exponential decay is y=a*b^x, where <em>a</em> is the initial amount, <em>b</em> = 1 + <em>r</em> (the growth rate as a decimal number) and <em>x</em> is the number of time periods (in this case, minutes).  Substituting the information we have:
y=430(1+-0.274)^1^9&#10;\\=430(1-0.274)^1^9&#10;\\=430(0.726)^1^9=0.98.  To the nearest tenth of a gram, this would be 1.0 grams.
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3 years ago
If you eat one quarter of a pizza and your dog eats one eighth of it, what percent is left over?
slamgirl [31]
Take 3 quarters minus one eighth and you’ll get ur answer
4 0
3 years ago
Solve the equation by completing the square 5x(x+6)=-50
motikmotik
First lets distribute the 5x 
5x^2 + 30x = -50

Lets divide every term by 5 
x^2 + 6x = -10 

To complete the square we have to half the b value, which in this case is 6. Then square it. 
Half of 6 is 3, 3 squared is 9 

Add that to both sides of the equation 
x^2 + 6x + 9 = -1 

Find the binomial squared
(x+3)^2 (If you're wondering how i got that please comment) 

(x+3)^2 = -1 

Take the square root of the equation of both sides
(x+3) = +/- i
x = -3 +/- i
x = -3 - i
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3 0
3 years ago
Can someone help me find the equivalent expressions to the picture below? I’m having trouble
miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is \frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}.

Now we will solve this expression with the help of law of exponents.

\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}

           =2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}

           =2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}

           =2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}

           =2^{\frac{2}{9}}\times 3^{-\frac{2}{3} } [Option 2]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2 [Option 1]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2

                =(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }

                =\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} } [Option 3]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }

               =\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}} [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0
2 years ago
Need help with this math
Rudiy27

10,171.07 pesos

To every US dollar, it equal 18.84 pesos.

7 0
3 years ago
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