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melomori [17]
4 years ago
15

Consider the following data set: 3, 4, 6, 7, 9, 9, 11. Identify a number you could add to the set to keep the mean smaller than

the median.
Mathematics
2 answers:
kifflom [539]4 years ago
5 0
The mean is simply the average of the data set. 

Mean = (3+4+6+7+9+9+11)/7 = 7

The median, on the other hand, is the middle data when you arrange them from least to greatest. The middle data here is 7. 

Hence, initially, the mean and median are equal. In order to make the mean less than median, add another data point which makes it the lowest. For example, we can add 1 as the new data point. The mean would be:

Mean = (1+3+4+6+7+9+9+11)/8 = 6.25

The median is (6+7)/2 = 6.5

Therefore, you can add any number less than 3. For example, that could be 1.
pishuonlain [190]4 years ago
4 0
You take to two numbers in the middle and add then (2+4) and that equals 6 so that is your mean. then you take you 6 and then you divide it by 2 (6/2) and that equals, 3 and that is the median.
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If y = 5x - 2 were changed to y = x - 2, how would the graph of the new function compare with the first one?
Brums [2.3K]

Every x coordinate of the first graph would be a multiple of 5. Example when x is 2, y = 8. The (x,y) coordinates for the first graph becomes (10,8). The second graph has a y value of 0 when x is 2. So its coordinate becomes (2,0). We see a trend here, the x coordinate of the second graph is 1/5 the x coordinate of the first graph.

7 0
4 years ago
Solving for x:<br> 15+8x=2x+7-5x
uysha [10]
15+8x=2x+7-5x

Subtract 8x from  both sides.
15=2x+7-5x-8x

Combine like terms.
15=-11x+7

Subtract 7 from both sides.
8=-11x

Divide -11 from both sides.
.73=x

Your answer is .72
8 0
3 years ago
A bike price is 159$ in january 2006 each year its price depreciates by 7 percent what will be its price at the end of 2007
Gemiola [76]

AnsPlayrules eteanat b.

Step-by-step expfnkel

6 0
3 years ago
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The probability that a person in the United States has type B​+ blood is 12​%. Three unrelated people in the United States are s
V125BC [204]

Answer:

The probability that all three have type B​+ blood is 0.001728

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have type B+ blood, or they do not. The probability of a person having type B+ blood is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a person in the United States has type B​+ blood is 12​%.

This means that p = 0.12

Three unrelated people in the United States are selected at random.

This means that n = 3

Find the probability that all three have type B​+ blood.

This is P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.12)^{3}.(0.88)^{0} = 0.001728

The probability that all three have type B​+ blood is 0.001728

4 0
3 years ago
HELPPPPPPP I'LL GIVE BRAINLY <br><br> 3x + 5 ≤ -13
romanna [79]

Answer:

Step-by-step explanation:

3x + 5 ≤ -13

     -5     -5

              -18

3x ≤ -18

3x divide by 3. Then divide the other side by three

x ≤ -6

im not 100% sure but thats how I would do it.

5 0
3 years ago
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