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2 years ago

A) 6 haircuts at Chez Diva costs $210 B) One haircut at the Hair Factory costs $20

Mathematics

1 answer:

Tpy6a [65]2 years ago

7 0

Answer:36

Step-by-step explanation: 210 divided by 6

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The sum of seven and the quotient of a number x and eight

salantis [7]

7 + (x/8) in written form. I hope this helps! -Dan

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2 years ago

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PLS HELP<br><br><br> Which equation describes the function shown in the table? <br>

evablogger [386]

Answer:

The first one

Step-by-step explanation:

Because it already give you the y-intercept and you can solve x by doing 4 to 7 have to add 3 and x only have to add 1. It will give you a slope 3/1, so it is 3.

y=3x+1

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2 years ago

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Ilya [14]

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Find the integration of (1-cos2x)/(1+cos2x)

slega [8]

Given:

The expression is:

$\dfrac{1-\cos 2x}{1+\cos 2x}$

To find:

The integration of the given expression.

Solution:

We need to find the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ .

Let us consider,

$I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx$

$I=\int \dfrac{2\sin^2x}{2\cos^2x}dx$ $[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]$

$I=\int \dfrac{\sin^2x}{\cos^2x}dx$

$I=\int \tan^2xdx$ $\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]$

It can be written as:

$I=\int (\sec^2x-1)dx$ $[\because 1+\tan^2 \theta =\sec^2 \theta]$

$I=\int \sec^2xdx-\int 1dx$

$I=\tan x-x+C$

Therefore, the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ is $I=\tan x-x+C$ .

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2 years ago

V1 - 2 sin cos 0 = cos 0 - sin

kramer

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2 years ago