<h3>
Answer:</h3>
3.342 x 10^24 molecules of water
<h3>
Explanation:</h3>
Given;
Mass of water = 100.0 g
Required to determine the number of molecules in 100.0 g of water
Using Avogadro's constant
1 mole of a compound contains 6.022 × 10^22 molecules
Thus;
1 mole of H₂O contains 6.022 × 10^23 molecules
But;
1 mole = 18.02 g/mol
Therefore;
18.02 g of water contains 6.022 × 10^23 molecules
100.0 g of water will have;
= (100. 0 g ×6.022 × 10^23 molecules) ÷ 18.02
= 3.342 x 10^24 molecules
I am pretty sure the Ag(s) is the reducing agent
anode reaction: Ag(s)+HCl(aq)⇒H⁺+AgCl(s)+e⁻
which means that H⁺ is the oxidizing agent
cathode reaction: 2H⁺(aq)+2e⁻⇒H₂(g)
and the cell reaction is the combination of the anode and cathode reactions.
cell reaction: 2Ag(s)+2HCl(aq)⇒2AgCl(s)+H₂(g)
Percentage by mass of water in CuSO4.5H20 is 36.07% .
In this problem we have - copper(II) sulfate pentahydrate and it's molecular formula is (CuSO₄.5H₂O) .
There are 5 molecules of water are present.
Now we calculate it's molar mass-
We know that-
molar mass of Cu = 63.5u
Molar mass of SO₄ = 96 u
Molar mass of H₂O = 18 u
Now, molar mass of (CuSO₄.5H₂O) = 63.5 + 96 + 5 × 18
Now, molar mass of (CuSO₄.5H₂O) = 249.5u
And mass of water in CuSO₄.5H₂O = 90 u
now mass percentage of water = mass of water ÷ Total mass ×100
now mass percentage of water = 90 ÷ 249.5 × 100
now mass percentage of water = 36.07 %
So we find out mass percent by dividing given mass with total mass and then multiplying it with hundred and it came out to be 36.07 % .
Learn more about mass percent here: brainly.com/question/13896694
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Answer:
A
Explanation:
though an ecosystem can support life forms,when they become over populated or unlimited there will be competition for food,Shelta and other basic necessities which will lead to many of these life forms dying
The first blank is elements and the second blank is compounds
