Dinitrogen tetraoxide, a colorless gas, exists in equilibrium with nitrogen dioxide, a reddish brown gas.

Chemistry

1 answer:

viktelen [127]3 years ago

3 0

Explanation:

N2O4(g) <----------> 2NO2(g)

Before proceeding,

A chemical equilibrium can be defined as a condition in the course of a reversible chemical reaction in which no net change in the amounts of reactants and products occurs.

Statement 1.

This statement is false. Equilibrium is not about equal concentrations but rather zero change in concentration of the reactants and products.

Statement 2.

This statement is True in chemical equilibrium; the forward and reverse reactions occur at equal rates.

Statement 3.

This statement is False. The rate constant for the forward reaction is not equal to the rate constant of the reverse reaction.

Statement 4.

The concentration of NO2 divided by the concentration of N2O4 is NOT equal to a constant. To obtain a constant value irregardless of the concentrations, the concentration of NO2 must be squared. This comes from the stoichiometry of the reaction

Kc= [NO2]2 / [N2O4]

This statement is false.

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Solubility

Inga [223]

Non electrolytes are Pentacarbon decahydride, Phosphorus pentachloride, Glucose.

Explanation:

Non electrolytes do not exist as ions in aqueous solution. Since it does not get dissociated into ions, these non electrolytes do not conduct electricity when it is dissolved or it is heated or melted.

Pentacarbon decahydride is a non electrolyte.

Magnesium chloride is an electrolyte.

Copper phosphate is an electrolyte

Sulfur trioxide is an electrolyte.

Aluminum oxide is an electrolyte

Phosphorus pentachloride do not get dissociated into its ions so it is a non-electrolyte.

Glucose gets dissolved in water but do not dissociate into ions, so it is a non electrolyte.

5 0

4 years ago

Consider the following multistep reaction:

chubhunter [2.5K]

The question is incomplete, here is the complete question:

Consider the following multistep reaction:

C+D⇌CD (fast)

CD+D→CD₂ (slow)

CD₂+D→CD₃ (fast)

C+3D→CD₃

Based on this mechanism, determine the rate law for the overall reaction.

Answer: The rate law for the reaction is $\text{Rate}=k'[C][D]^2$

Explanation:

Rate law is the expression which is used to express the rate of the reaction in terms of the molar concentration of reactants where each term is raised to the power their stoichiometric coefficient respectively from a balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

For the given chemical reaction:

$C+3D\rightarrow CD_3$