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3 years ago

What is the overall charge of the compound frfr

Chemistry

1 answer:

matrenka [14]3 years ago

3 0

Answer:

As any molecular or ionic compound, 0 net charge, as a hypothetical diatomic cation, 2+

Explanation:

The question states that this is a compound, and any molecular or ionic compound would have a net charge of 0.

However, such a compound doesn't exist. Francium generally exists in nature having a 1+ charge in its cation form. Combining two francium ions would result in a $Fr_2^{2+}$ species which is simply a diatomic ion but not a compound.

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faltersainse [42]

The SI unit of time in seconds

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2 years ago

Which of the following would increase the strength of an electromagnet? Check all that apply.

TiliK225 [7]

Answer: The correct statements are ; A and B.

Explanation:

The strength of the magnetic field(B) in an electromagnet can be calculated using formula:

$B=\mu\frac{N}{L}I$

$\mu$ = Relative permeability

N = number of turns

I = Current in the wire of the solenoid

L = length of the solenoid or electromagnetic

As we can see from the formula:

$B\propto N$

$B\propto I$

So, by increasing the turns and increasing current flowing through wire one can increase the strength of an electromagnet.

Hence, the correct statements are ; A and B.

5 0

2 years ago

Dilution question In many of the experiments, you will be asked to prepare a standard solution by diluting a stock solution. You

riadik2000 [5.3K]

Answer:

We could do two 1:50 dilutions and one 1:4 dilutions.

Explanation:

Hi there!

A solution that is 1000 ug/ ml (or 1000 mg / l) is 1000 ppm.

Knowing that 1 ppm = 1000 ppb, 100 ppb is 0.1 ppm.

Then, we have to dilute the stock solution (1000 ppm / 0.1 ppm) 10000 times.

We could do two 1:50 dilutions and one 1:4 dilutions (50 · 50 · 4 = 10000). Since the first dilution is 1:50, you will use the smallest quantity of the stock solution (if we use the 10.00 ml flask):

First step (1:50 dilution):

Take 0.2 ml of the stock solution using the third dispenser (20 - 200 ul), and pour it in the 10.00 ml flask. Fill with water to the mark (concentration : 1000 ppm / 50 = 20 ppm).

Step 2 (1:50 dilution):

Take 0.2 ml of the solution made in step 1 and pour it in another 10.00 ml flask. Fill with water to the mark. Concentration 20 ppm/ 50 = 0.4 ppm)

Step 3 (1:4 dilution):

Take 2.5 ml of the solution made in step 3 (using the first dispenser 1 - 5 ml) and pour it in a 10.00 ml flask. Fill with water to the mark. Concentration 0.4 ppm / 4 = 0.1 ppm = 100 ppb.

6 0

3 years ago

How many liters of 3.5 M solution can be made using 23 moles of LiBr *must show work to get credit*

MrMuchimi

<u>Answer:</u> 6.57 L of solution can be made.

<u>Explanation:</u>

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (L)}}$ .....(1)

Given values:

Molarity of LiBr = 3.5 M

Moles of LiBr = 23 moles

Putting values in equation 1, we get:

$3.5mol/L=\frac{23mol}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{23mol}{3.5mol/L}=6.57L$

Hence, 6.57 L of solution can be made.

5 0

3 years ago

I’ll give 5 stars and Brainliest plus this is 20 points lol

Daniel [21]

Answer:

I think is b

Explanation:

4 0

2 years ago