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Tomtit [17]
3 years ago
8

Write the slope intercept form of the equation of the line.Help

Mathematics
2 answers:
White raven [17]3 years ago
8 0

Answer:

Our final equation is \bold{y = \frac{1}{4}x + 3}.

Step-by-step explanation:

We are given a coordinate point and the slope of a line. We need to know that:

  • The slope-intercept form of a line is \text{y = mx + b}, where <em>m</em> is the slope of the line and <em>b</em> is the y-intercept of the line.
  • The point-slope formula is y - y₁ = m(x - x₁).

We want to end up at the slope-intercept form of the equation. Therefore, we can use the point-slope formula and substitute our values and solve the equation.

y - 2 = \frac{1}{4}(x - (-4))\\\\y - 2 = \frac{1}{4}x + 1\\\\\small\boxed{\bold{y = \frac{1}{4}x + 3}}

Therefore, we have determined that our equation in slope-intercept form is \bold{y = \frac{1}{4}x + 3}.

Sindrei [870]3 years ago
5 0

\huge\boxed{y=\frac{1}{4}x+3}

Hey! Let's start off with the point-slope form equation:

y-y_1=m(x-x_1)

In this equation, m represents the slope and (x_1, y_1) is the known point.

Substitute in the values we know:

y-2=\frac{1}{4}(x-(-4))

Subtracting a negative number is the same as adding a positive number.

y-2=\frac{1}{4}(x+4)

Distribute the \frac{1}{4}:

y-2=\frac{1}{4}x+1

Add 2 to both sides to get the equation in slope-intercept form, which is y=mx+b:

\boxed{y=\frac{1}{4}x+3}

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