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3 years ago

Solve and state any extraneous solutions

Mathematics

1 answer:

Mice21 [21]3 years ago

3 0

$\frac{3x}{x - 1} + 2 = \frac{3}{x - 1}$

$\frac{3x}{x - 1} + \frac{2(x - 1) }{ x - 1} = \frac{3}{x - 1}$

$\frac{3x}{x - 1} + \frac{2x - 2}{ x - 1} = \frac{3}{x - 1}$

$\frac{3x + 2x - 2}{ x - 1} = \frac{3}{x - 1}$

$3x + 2x - 2 = 3$

$5x - 2 = 3$

$5x = 3 + 2$

$5x = 5$

$x = \frac{5}{5}$

$x = 1$

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Aleks04 [339]

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<u>Step-by-step explanation:</u>

Let the number of tickets sold to the individuals = s

Let the number of tickets sold to the couples = c

According to the question,

s + c = 46 ( Equation 1)

Since each individual's ticket is $6, the total amount of money made by selling tickets to individuals is 6s.

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3 years ago

A right pyramid with a regular hexagon base has a height of 3 units If a side of the hexagon is 6 units long, then the apothem i

Setler79 [48]

Answer:

Part a) The slant height is $3\sqrt{2}\ units$

Part b) The lateral area is equal to $54\sqrt{2}\ units^{2}$

Step-by-step explanation:

we know that

The lateral area of a right pyramid with a regular hexagon base is equal to the area of its six triangular faces

$LA=6[\frac{1}{2}(b)(l)]$

where

b is the length side of the hexagon

l is the slant height of the pyramid

Part a) Find the slant height l

Applying the Pythagoras Theorem

$l^{2}=h^{2} +a^{2}$

where

h is the height of the pyramid

a is the apothem

we have

$h=3\ units$

$a=3\ units$

substitute

$l^{2}=3^{2} +3^{2}$

$l^{2}=18$

$l=3\sqrt{2}\ units$

Part b) Find the lateral area

$LA=6[\frac{1}{2}(b)(l)]$

we have

$b=6\ units$

$l=3\sqrt{2}\ units$

substitute the values

$LA=6[\frac{1}{2}(6)(3\sqrt{2})]=54\sqrt{2}\ units^{2}$

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3 years ago

Read 2 more answers

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aalyn [17]

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Solve this and you get:

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3 years ago

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What is the volume of a sphere with a diameter of 6 m, rounded to the nearest tenth of a cubic meter?

seraphim [82]

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Step-by-step explanation:

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