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Paraphin [41]
3 years ago
7

Solve and state any extraneous solutions

Mathematics
1 answer:
Mice21 [21]3 years ago
3 0

\frac{3x}{x - 1}  + 2 =  \frac{3}{x - 1}

\frac{3x}{x - 1} +  \frac{2(x - 1) }{ x - 1}   =  \frac{3}{x - 1}

\frac{3x}{x - 1}  +  \frac{2x - 2}{ x - 1}  =  \frac{3}{x - 1}

\frac{3x + 2x - 2}{ x - 1}  =  \frac{3}{x - 1}

3x + 2x - 2 = 3

5x - 2 = 3

5x = 3 + 2

5x = 5

x =  \frac{5}{5}

x = 1

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