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MariettaO [177]
3 years ago
14

Please help me! this is important.

Mathematics
1 answer:
Dafna11 [192]3 years ago
7 0
I’m guessing C , shi mad confusing
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What is being distributed in the following problem?<br> 5 - 31d + 7)
USPshnik [31]

Answer:

the -3 is being distributed. --> the 5 stays outside till the end. multiply the 3 inside first, then the negative. and then add the 5 to the final answer            

             5-3(d+21)  = -->> 5-(3d+21)=--->>>5-3d-21=3d-16

Step-by-step explanation:

5-3(d+21) =

5-(3d+21)=

5-3d-21=

ans=3d-16

7 0
3 years ago
this isn’t a question but i just wanted to tell everyone you all are doing great. this year has been hard and everyone is workin
BlackZzzverrR [31]

Thank you so much friend.

I think a advantage of this will be that we will be able to tell our grandchildren about how we survived the pandemic, just like our grandparents talk about World War. Lol.

3 0
2 years ago
Read 2 more answers
Help please!!!!!!!!!
In-s [12.5K]

ANSWER

24


EXPLANATION

For a matrix A of order n×n, the cofactor C_{ij} of element a_{ij} is defined to be


   C_{ij} = (-1)^{i+j} M_{ij}


M_{ij} is the minor of element a_{ij} equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.


Here, we have


   C_{11} = (-1)^{1+1} M_{11} = M_{11}


M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right)  \end{aligned}


Since the determinant of a 2×2 matrix is


   \det\left(  \begin{bmatrix} a & b \\ c& d  \end{bmatrix} \right) = ad-bc


it follows that


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \\ &= (0)(-8) - (-3)(8) \\ &= -(-24) \\ &= 24 \end{aligned}


so C_{11} = M_{11} = 24

4 0
3 years ago
?????????????????????
valentinak56 [21]

Step-by-step explanation:

\huge \: 2 \sqrt{x} .4  {x}^{ -  \frac{5}{2} } \\  \\   \huge \: = 2.4 {x}^{ \frac{1}{2} }  . {x}^{ -  \frac{5}{2} } \\  \\ \huge \:   = 8 {x}^{ \frac{1}{2}  -  \frac{5}{2} }  \\  \\   \huge \: = 8 {x}^{ \frac{1 - 5}{2} }  \\  \\ \huge \:   = 8 {x}^{ -  \frac{4}{2} }  \\  \\ \huge \:   = 8. {x}^{ - 2}  \\

4 0
3 years ago
Trina has two brothers. one brother is 7 years older than trina and the other brother is 7 years younger than trina. the product
AlladinOne [14]
(a) 95 = (x+7)*(x-7)

(b) 95 = (x+7)*(x-7) 
Expand the brackets:
95 = x² -7x + 7x -49 = x² - 49
Subtract x² from both sides:
95-x² = -49
Subtract 95 from both sides:
-x²=-49-95 
-x²= -144
Divide both sides by -1 to get rid of the negative numbers:
-x²/-1=-144/-1
x²=144
Take the square root of 144:
x = ± squareroot of 144
x = 12 or -12
x = 12 because you cannot have a negative age so Trina is 12 years old.
     
7 0
3 years ago
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