9514 1404 393
Answer:
H y +268 = 12(x +20)
Step-by-step explanation:
The point-slope form of the equation for a line is ...
y -k = m(x -h) . . . . . . line with slope m through point (h, k)
The first point in the table is (x, y) = (-20, -268), so the equation with these filled in is ...
y -(-268) = m(x -(-20))
y +268 = m(x +20) . . . . . . matches F or H
We can see that the values of y change by a lot more than the values of x. That means the slope is a lot more than 1. This observation eliminates choice F, so we are left with ...
H. y +268 = 12(x +20)
F(x)=2x/(x-1)
Denominator cannot be equal 0.
x-1=0
x=1 is vertical asymptote.
To find horizontal asymptote
we need divide the coefficients before x
y=2x/x=2,because when x becomes really big (x---->∞) , value of 1 will not influence the result .
y=2 is horizontal asymptote
Answer:
D
Step-by-step explanation:
![f(x)=(x-1)(x^2+2)^3\\f'(x)=(x-1)*3(x^2+2)^2*2x+(x^2+2)^3*1\\f'(x)=6x(x-1)(x^2+2)^2+(x^2+2)^3\\f'(x)=(x^2+2)^2[6x^2-6x+x^2+2]\\f'(x)=(x^2+2)^2(7x^2-6x+2)\\D](https://tex.z-dn.net/?f=f%28x%29%3D%28x-1%29%28x%5E2%2B2%29%5E3%5C%5Cf%27%28x%29%3D%28x-1%29%2A3%28x%5E2%2B2%29%5E2%2A2x%2B%28x%5E2%2B2%29%5E3%2A1%5C%5Cf%27%28x%29%3D6x%28x-1%29%28x%5E2%2B2%29%5E2%2B%28x%5E2%2B2%29%5E3%5C%5Cf%27%28x%29%3D%28x%5E2%2B2%29%5E2%5B6x%5E2-6x%2Bx%5E2%2B2%5D%5C%5Cf%27%28x%29%3D%28x%5E2%2B2%29%5E2%287x%5E2-6x%2B2%29%5C%5CD)
I hope this helps you
6x^2-19x+10
3x -2
2x -5
(3x-2)(2x-5)
