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2 years ago

The sum of twice a number, m, and 7 is equal to 15 less than the number,

Mathematics

1 answer:

Sunny_sXe [5.5K]2 years ago

4 0

Answer:

2m+7 = m-15

2m-m+7 = -15

1m = -15-7

1m = -22

m = -22

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Which expression is equivalent to the expression below? StartFraction 6 c squared 3 c Over negative 4 c 2 EndFraction divided by

Fudgin [204]

The given equation $(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)$ is equivalent to the expression -3c.

Given that, the expression can be written as.

$(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)$

By simplifying the above equation,

$\dfrac{6c^2+3c}{-4c+2}\div \dfrac{2c+1}{4c-2}$

By taking out the common terms from the equation,

$\dfrac{3c(2c+1)}{2(-2c+1)}\div\dfrac{2c+1}{2(2c-1)}$

By simplifying the above equation by cancel out the common factors.

$\dfrac{3c}{-2c+1} \div \dfrac{1}{2c-1}$

Now, by taking (-1) common from (-2c+1) we get,

$\dfrac{3c}{-1(2c-1)} \div \dfrac{1}{2c-1}$

By simplifying the above equation, we get the expression,

$-3c$

So the given equation $(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)$ is equivalent to the expression -3c.

For more details, follow the link given below.

brainly.com/question/1301963.

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2 years ago

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago