How do I simplify (y^3)^3 without parentheses?

2 answers:

7 0

We multiply the exponents outside of the parenthesis to all the exponents inside the parenthesis.

$\sf(y^3)^3\rightarrow~y^{3\times3}\rightarrow~\boxed{\sf~y^9}$

riadik2000 [5.3K]3 years ago

3 0

We will use this property in exponents to answer your question:

$\sf{(a^b)^c=a^{b\times c}}$

So basically we multiply the exponents when it is outside of the parenthesis. So:

$\sf{(y^3)^3=y^{3\times3}}$

$\sf{=y^9}$

So your answer would be $\boxed{\sf{y^9}}$

You might be interested in

Can someone help me with this task please?

sesenic [268]

Answer:

look at the picture i sent please

6 0

2 years ago

A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas

WITCHER [35]

Answer:

$P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68$

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

$P(A) = 0.8, P(B) = 0.2$

We are assuming that the two events are independent so then we have the following propert:

$P(A \cap B ) = P(A) * P(B)$

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

$P(B' \cup A')$