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Maksim231197 [3]

3 years ago

6

A public swimming pool that holds 45,000 gallons of water is going to be drained for maintenance at a rate of 100 gallons per mi

nute. The amount of water w (in gallons) in the pool after t minutes is given by the function w = 45,000 - 100t. Graph the function. Identify its domain and range. How much water is in the pool after 60 minutes? How many minutes will it take to empty the pool?

1 answer:

neonofarm [45]3 years ago

5 0

Answer: for the first question, after an hour there would be 39,000 gallons left and it would take 450 minutes to drain the pool

Step-by-step explanation:

You multiple the minutes with the rate or which the gallons are being drained and subtract it by the total amount,

Ps can I get the brainliest answer

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zlopas [31]

Answer:

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Step-by-step explanation:

Given

Total number of questions in the paper = 28

Out of these 28 questions let us say that x number of questions are of 2 points and 28-x questions are of 4 points.

Also, the complete test is of 100 marks

Thus, the linear equation representing the

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8 0

3 years ago

A circle has the equation 2x²+12x+2y²−16y−150=0.

KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

$(x-h)^{2} +(y-k)^{2}=r^{2}$ (1)

Where $(h,k)$ are the coordinates of the center and $r$ is the radius.

Now, we are given the equation of this circle as follows:

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And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

$2(x^{2}+6x+y^{2}-8y-75)=0$ (3)

Rearranging the equation:

$x^{2}+6x+y^{2}-8y=75$ (4)

$(x^{2}+6x)+(y^{2}-8y)=75$ (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of $(a\pm b)^{2}=a^{2}\pm+2ab+b^{2}$ :

<u>For the first parenthesis:</u>

$x^{2}+6x+b^{2}$

We can rewrite this as:

$x^{2}+2(3)x+b^{2}$

Hence in this case $b=3$ and $b^{2}=9$ :

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<u>For the second parenthesis:</u>

$y^{2}-8y+b^{2}$

We can rewrite this as:

$y^{2}-2(4)y+b^{2}$

Hence in this case $b=-3$ and $b^{2}=9$ :

$y^{2}-2(4)y+4^{2}=y^{2}-8y+16=(y-4)^{2}$

Then, equation (5) is rewritten as follows:

$(x^{2}+6x+9)+(y^{2}-8y+16)=75+9+16$ (6)

<u>Note we are adding 9 and 16 in both sides of the equation in order to keep the equality.</u>

Rearranging:

$(x-3)^{2}+(y-4)^{2}=100$ (7)

At this point we have the circle equation in the center radius form $(x-h)^{2} +(y-k)^{2}=r^{2}$

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8 0

3 years ago

a boat cost $12050 and decreases in value by 12% per year. how much will the boat be worth after 9 years

sweet [91]

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BigorU [14]

Answer:

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Step-by-step explanation:

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Kipish [7]

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6 0

3 years ago

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