The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
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You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
P = 2a + b
10= 2a + 3
2a = 10-3
a = 7/2 = 3.5
Therefore, numerical value of a is 3.5
Answer:
Either d or b and b looks like it works hte best
Step-by-step explanation:
Answer:
Step-by-step explanation:
CORN VIRUS IS A
HOAX
The median is 42, the lower is 36, and the upper is 86