Ok let’s solve it
5(x-2)^2-20=0
first let’s foil (x-2)
5(x^2-4x+4) -20=0
now distribute the 5
5x^2 -20x +20 -20 = 0
combine like terms
5x^2-20x=0
take the gcf
5x(x-4)=0
x=0, 4
solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k
Answer:
The answer is (4x-1)·(3x+2)
Step-by-step explanation:
It would be 79.4, if you follow complete it in the correct order. (mathematically)
Answer: 1) (0,-3) 2) (4,-2) 3) (2,3) 4) (-2,2)
Step-by-step explanation: Hope this helps!
Step-by-step explanation:
i don't get the question
