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garri49 [273]
3 years ago
7

3 lines are shown. A line with points P, R, N intersects a line with points M, R, O at point R. A line extends from point R to p

oint L between angle P R M.
Which angles form a linear pair?

AnglePRL and AngleLRM
AngleORP and AngleMRN
AngleMRN and AngleNRO
AngleLRP and AngleORP
Mathematics
2 answers:
trasher [3.6K]3 years ago
8 0

Answer:

c

Step-by-step explanation:

yuradex [85]3 years ago
3 0

Answer:

The answer is C

Step-by-step explanation:

This is right because that's what I did

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How many miles equals 26 km
Sliva [168]

Given data:

The given distance is d=26 km.

We know 1 kilometer is equal to approx 0.621 miles.

1km= 0.621 miles

Multiply the above expression with 26 on both sides.

26(1 km)= 26(0.621 miles)

26 km= 16.146 miles.

Thus, 26 kilometer is equal to 16.146 miles

4 0
1 year ago
Describe the transformation f(x) = 2x + 1 -> g(x) = -8(x + 4) - 1
katrin2010 [14]

f(x) = 2x + 1; Paren graph = x;

The graph was shifted one unit up and stretched 2 times.

g(x) = -8(x+4) - 1 = -8x - 32 - 1 = -8x - 33

The graph was shifted 33 units down and stretched 8 times and flipped 180 degrees.

8 0
3 years ago
What is the square root of 28
GrogVix [38]

Answer:5. 291503

Step-by-step explanation:

√28

2√7

5. 291503

8 0
3 years ago
An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th
monitta

Answer:

a) n =1623

b) ME=2.0538\sqrt{\frac{0.21 (1-0.21)}{1623}}=0.0208    

Step-by-step explanation:

1) Notation and definitions

n random sample taken

\hat p=0.19 estimated proportion of customers are not satisfied with the service provided by the local dealer

Confidence =0.96 or 96%

Me= 0.02 represent the margin of error

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 96% of confidence, our significance level would be given by \alpha=1-0.96=0.04 and \alpha/2 =0.02. And the critical value would be given by:

z_{\alpha/2}=-2.0538, z_{1-\alpha/2}=2.0538

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.02 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.19(1-0.19)}{(\frac{0.02}{2.0538})^2}=1622.912  

And rounded up we have that n=1623

Part b

The margin of error is given by:

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    

So then if w replace the value of n obtained from part a we got:

ME=2.0538\sqrt{\frac{0.21 (1-0.21)}{1623}}=0.0208    

3 0
3 years ago
How do i find the unit rate?
Assoli18 [71]
U can find the unit rate by looking where is the point so in that pic the unit rate I see is: 3/5
5 0
3 years ago
Read 2 more answers
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