Let
b-----------> the length side of the square box
h------------> the height of the box
SA---------> surface area of the box
we know that
[volume of the box]=b²*h
volume=256 in³
b²*h=256-------> h=256/b²-----> equation 1
surface area of the box=area of the base+perimeter of base*height
area of the base=b²
perimeter of the base=4*b
surface area=b²+(4*b)*h------> SA=b²+4*b*h-----> equation 2
substitute equation 1 in equation 2
SA=b²+4*b*[256/b²]-----> SA=b²+1024/b-----> SA=(b³+1024)/b
the answer is
the formula of the volume of the box is V=b²*h-----> 256=b²*h
the formula of the surface area of the box are
SA=b²+4*b*h
SA=(b³+1024)/b
Hint to start out the problem:
eg. For f(4), use the first expression, (x-3)^2 because 4 is greater than 1.
Answer:
Isn't it 18?
Step-by-step explanation:
Because you need to add 4 and 2 then multiply it with 3?
The area of the two triangular bases is
(total base area) = 2×(1/2)bh
= bh
= (10 m)(6 m) = 10·6 m² = 60 m²
The area of the three rectangles making up the remaining faces of the prism is
(total lateral area) = length×base + length×height + length×hypotenuse
= length×(base + height + hypotenuse)
= (16 m)(10 m + 6 m + 11.6 m)
= (16 m)(27.6 m) = 16·27.6 m² = 441.6 m²
Then the surface area of the prism is the sum of these
surface area = total base area + total lateral area
= 60 m² + 441.6² = 501.6 m²
When rounded to the nearest whole number, this is
A) 502 m²
