(X-3)(X+1)=0
X-3=0
X=3
X+1=0
X=-1
From the information given;
1 bag of concrete = 1000 in^3
2 bags at home = 1000*2 = 2000 in^3
The available space has a volume of;
Volume = (5*12)*10*10 (Note: 1 ft = 12 inches)
Volume = 60*10*10 = 6000 in^3
The remaining volume = Available space - occupied space = 6000 - 2000 = 4000 in^2
1 bag = 1000 in^3
x bags = 4000 in^2
Then,
x = 1*4000/1000 = 4 bags.
This means 4 more bags of concrete will be required to fully fill the space.
14/4 > 1 is what it looks like.
Answer:
(d) All of the above
Step-by-step explanation:
In order to solve this question we will have to find out which numbers are located in which group (the group of numbers are U, B, B').
So lets start of with finding out what numbers are a part of group U. By looking at that picture we can see that all number on the graph are a part of group U. So.....
U = {0,1,2,3,4,5,6,7,8,9}
Then we can find out what numbers are part of the group B. We just have to include the numbers that are located within the circle and exclude all of the numbers out side of the circle. So........
B = {0,1,4,5,6,7,8}
We find numbers that are parts of group B' by using a similar method that we used to find out what numbers were part of group B (Just this time we include all numbers outside of the circle and exclude all of the numbers inside the circle). So ......
B' = {2,3,9}
Now we see that the right option is option d.
