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Tcecarenko [31]
3 years ago
5

Balanced chemical equation for formation of bleaching powder?​

Chemistry
2 answers:
poizon [28]3 years ago
8 0

Answer:

Ca(OH)2 + Cl2 → CaOCl2 +H2O.

Explanation:

Updated answer

morpeh [17]3 years ago
5 0

Answer:

this is balanced equation

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How many sodium ions are in 4543.3 g of NaCl?
Stella [2.4K]

Answer:

4.68x10²⁵ ions of Na⁺

Explanation:

First of all, we dissociate the salt:

NaCl(aq) → Na⁺(aq) + Cl⁻(aq)

An aqueous solution of NaCl dissociates in chlorides anions and sodium cations. Ratio is 1:1, per 1 mol of NaCl, we have 1 mol of Na⁺

We determine the moles of salt: 4543.3 g . 1mol / 58.45 g = 77.7 moles

77.7 moles are the amount of NaCl, therefore we have 77.7 moles of Na⁺.

We count the ions:

1 mol fo Na⁺ has 6.02x10²³ ions

77.7 moles of Na⁺ must have (77.7 . 6.02x10²³) / 1 = 4.68x10²⁵ ions of Na⁺

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