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3 years ago

Which is not a particle within an atom?

Chemistry

2 answers:

Karolina [17]3 years ago

8 0

Ion because the proton represents positive charge while electron represents negative charge and neutron is a main part

Karolina [17]3 years ago

6 0

Answer:

an ion

Explanation:

An ion is an atom or molecule with a net electric charge due to the loss or gain of one or more electrons. This is not a particle within an atom

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Can someone please help me with this, i'll give you a 5 star rating and the brainliest answer!

elena-s [515]

Answer:

A. equation

B. atoms

C. products

Explanation:

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3 years ago

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If we put 1g samples of all four of these into a hot oven, which would absorb the most heat in order to reach 100 degrees Celsiu

Fiesta28 [93]

Answer:

Ice

Explanation:

The Ice would absorb heat to change the temperature from anything below 1 degree celsius in order to become liquid water. After being a liquid water it'd absorb further amount of energy in order to increase it's temperature to 100 degrees. Therefore, the Ice absorb more water

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3 years ago

kondor19780726 [428]

Explanation:

It is known that 1 gram contains 1000 milligrams. And, mathematically we can represent it as follows.

$\frac{1 g}{1000 mg}$ or $\frac{1000 mg}{1 g}$

So, when we have to convert grams into milligrams then we simply multiply the digit with 1000. And, if we have to convert a digit from milligrams to grams then we simply divide it by 1000.

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3 years ago

The estimated heat of vaporization of diethyl ether using the Chen's rule is A. 29.7 KJ/mol B. 33.5 KJ/mol C. 26.4 KJ/mol D. 36.

Brums [2.3K]

Answer:

C. 26.4 kJ/mol

Explanation:

The Chen's rule for the calculation of heat of vaporization is shown below:

$\Delta H_v=RT_b\left [ \frac{3.974\left ( \frac{T_b}{T_c} \right )-3.958+1.555lnP_c}{1.07-\left ( \frac{T_b}{T_c} \right )} \right ]$

Where,

$\Delta H_v$ is the Heat of vaoprization (J/mol)

$T_b$ is the normal boiling point of the gas (K)

$T_c$ is the Critical temperature of the gas (K)

$P_c$ is the Critical pressure of the gas (bar)

R is the gas constant (8.314 J/Kmol)

For diethyl ether:

$T_b=307.4\ K$

$T_c=466.7\ K$

$P_c=36.4\ bar$

Applying the above equation to find heat of vaporization as:

$\Delta H_v=8.314\times307.4 \left [ \frac{3.974\left ( \frac{307.4}{466.7} \right )-3.958+1.555ln36.4}{1.07-\left ( \frac{307.4}{466.7} \right )} \right ]$