Does anyone know the answer to both these questions ???
1 answer:
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Answer:
The answer is True
Step-by-step explanation:
A <em>mathematical induction</em> consists in only 2 steps:
<u>First step</u>: Show the proposition is true for the first one valid integer number.
<u>Second step</u>: Show that if any one is true then the next one is true
Finally, if first step and second step are true, then the complete proposition is true.
So, given
First step: using and replacing n=2 (the first valid integer number >1)
As the result is an integer number, so the first step is true.
Second step: using any next number, , let it replace
As the First step is true, we know that
,
So let it replace in the previous expression
Finally
where the last expression is an integer number
So the second step is true, and the complete proposition is True
Answer:
i. ΔAXC ~ ΔCXB
ii. ΔBCX Is-congruent-to ΔACX
Step-by-step explanation:
From the given ΔABC, CX is the altitude of ΔABC; and also an angle bisector of <ACB.
So that:
m<AXC = m<BXC (right angle property)
m<ACX = m<BCX (congruent property)
m<ACX + m<AXC + m<CAX = (sum of angles in a triangle)
m<BCX + m<BXC + m<CBX = (sum of angles in a triangle)
Therefore, from the figure it can be deduced that;
i. ΔAXC ~ ΔCXB (Angle-Angle-Side, AAS, property)
ii. ΔBCX Is-congruent-to ΔACX (Angle-Angle-Side, AAS, property)