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3 years ago

1) Complete as sentenças:

Mathematics

1 answer:

Jobisdone [24]3 years ago

3 0

Answer:

$\huge\color{yellow}\boxed{Answer:}$

Step-by-step explanation:

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A rectangle width is one fourth it’s length, outs are is 9 square units. The equation I(1/4I)=9 can be used to find I, the lengt

OlgaM077 [116]

Answer:

The length of rectangle is 6 units and the width is 1.5 units

Step-by-step explanation:

Let

L -----> the length of rectangle

W ----> the width of rectangle

we know that

The area of rectangle is equal to

$A=LW$

we have

$A=9\ units^{2}$

$9=LW$ -----> equation A

A rectangle width is one fourth it’s length

$W=\frac{1}{4}L$ ----> equation B

substitute equation B in equation A and solve for L

$9=L(\frac{1}{4}L)$

$L^{2}=9*4$

$L^{2}=36$

take square root both sides

$L=6\ units$

Find the value of W

$W=\frac{1}{4}(6)$

$W=1.5\ units$

5 0

3 years ago

∠1 and ∠2 are complementary angles. m∠1=13° What is the measure of ∠2 ?

marin [14]

Measure of angle 2 is 77. hope this helped.

4 0

3 years ago

What is the area of the following polygon? Explain your process for how you arrived at the final area. Show your work

Reptile [31]

46 because 14+13=46 and cm

7 0

3 years ago

I lowkey need help on this whos got the answer

Mariana [72]

find the area A=b*h/2

bases=11

height=23

A=11*23/2

A=126.5 square unit

7 0

3 years ago

Read 2 more answers

Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms

miv72 [106K]

Hint :-

Break the given sequence into two parts .
Notice the terms at gap of one term beginning from the first term .They are like $\dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ . Next term is obtained by multiplying half to the previous term .
Notice the terms beginning from 2nd term , $4,7,10,13$ . Next term is obtained by adding 3 to the previous term .

Solution :- 

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

$\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ .

We can see that this is in Geometric Progression where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

$\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]$

Notice the term $\dfrac{1}{2^{25}}$ will be too small , so we can neglect it and take its approximation as 0 .

$\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]$

$\\\implies \boxed{ S_1 \approx 1 }$

$\rule{200}2$

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

$\implies S_2=\dfrac{n}{2}[2a + (n-1)d]$

Substitute ,

$\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}$

Hence sum = 908 + 1 = 909

7 0

3 years ago