Answer:
28
Step-by-step explanation:
12+[(15-5)]+(9-3)]
PEMDAS
Parentheses first
12+[(10)]+(6)]
Then add
12+10+6
Answer:
- 6. See solution
- 7. k = 2, k = -6
Step-by-step explanation:
6.
<u>Given equation:</u>
- The sum of the roots is q1 and the product of the roots is q2
Need to show that q1+q2 = 0
<h3>Solution</h3>
<u>Bringing the equation into standard form of ax² + bx + c = 0:</u>
- 2(x + 2)² + p(x + 1) = 0
- 2x² + 8x + 8 + px + p = 0
- 2x² + (p + 8)x + (p + 8) = 0
<u>Sum of the roots: </u>
<u>Product of the roots:</u>
<u>We see that q1 and q2 are opposite numbers, therefore their sum equals zero:</u>
- q1 + q2 = -(p + 8)/2 + (p + 8)/2 = 0
=============================================
7.
<u>Given quadratic equation:</u>
Need to find the possible values of k
<h3>Solution</h3>
<u>When the quadratic equation has equal roots, then its discriminant is equal to zero:</u>
- D = 0
- √b² - 4ac = 0
- √(-k -2)² - 4*1*4 = 0
- √k² + 4k + 4 - 16 = 0
- √k² + 4k - 12 = 0
- k² + 4k - 12 = 0
- k = {-4 ± √4² -4*1*(-12)}/2
- k = (-4 ± √16 + 48)/2
- k = (-4±√64)/2
- k = -2 ± 4
- k = 2, k = -6
If she uses the blue book then she will need,
544/9 ≈ 61 pages
If she uses the red book the she will need,
544/7 ≈ 78 pages
So she will need 17 more pages if she uses the red book.
Hope this helps :)
Answer:
9 tokens
Step-by-step explanation:
5 = Amount of friends
12 = Amount of tokens that Will takes
57 = total amount of tokens.
45 = amount of tokens left over after Will takes 12.
57 - 12 = 45

9
Step-by-step explanation:
Side CF is <em>1</em><em>0</em><em> </em><em>due</em><em> </em><em>to</em><em> </em><em>opposite</em><em> </em><em>sides</em><em> </em><em>paralleogram</em><em> </em><em>theorem</em>
<em>FE</em><em> </em><em>is</em><em> </em><em>1</em><em>5</em><em> </em><em>also</em><em>.</em>
<em>CE</em><em> </em><em>is</em><em> </em><em>1</em><em>4</em><em> </em><em>since</em><em> </em><em>it</em><em> </em><em>bisects</em><em> </em><em>it</em><em> </em><em>other</em><em> </em><em>half</em>
<em>GD</em><em> </em><em>is</em><em> </em><em>1</em><em>1</em><em> </em><em>since</em><em> </em><em>it</em><em> </em><em>half</em><em> </em><em>of</em><em> </em><em>2</em><em>2</em><em>.</em>