This can be solved by finding the number of permutations of the eight performers who will all perform before the one who insists on being the last.
The half-life of a substance is the amount of time it takes for half of the amount of substance to decay. The half-life of a pes
1 answer:
Answer:
15.625 grams
Step-by-step explanation:
The decay is First order reaction
The half life of the first order reaction is given by
T(1/2) = ㏑2/K
where K is the reaction constant for the first order reaction
T(1/2) = 2
2 = ln 2 /K
K = ln2/2
The equation of the first order reaction is given by
Kt = ln ()
where
t = time = 10years
Ro = initial concentration
R = amount left after time t
upon substituting the values
5ln2 = ln (500/R)
ln = ln (500/R) (a*lnb = ln
)
R = 500/32 = 15.625grams
Therefore the amount of pesticide left after 10 years is 15.625grams
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Answer: (-2, 0) and (0, -2)
Step-by-step explanation:
This system is:
y + x = -2
y = (x + 1)^2 - 3
To solve this we first need to isolate one of the variables in one fo the equations, in the second equation we have already isolated the variable y, so we can just replace it in the first equation:
(x + 1)^2 - 3 + x = -2
Now we can solve this for x.
x^2 + 2*x + 1 - 3 = -2
x^2 + 2*x + 1 -3 + 2 = 0
x^2 + 2*x + 0 = 0
The solutions of this equation are given by the Bhaskara's formula, then the solutions are:
The two solutions are:
x = (-2 - 2)/2 = -2
In this case, we replace this value of x in the first equation and get:
y - 2 = -2
y = -2 + 2 = 4
This solution is x = -2, y = 0, or (-2, 0)
The other solution for x is:
x = (-2 + 2)/2 = 0
If we replace this in the first equation we get:
y + 0 = -2
y = -2
This solution is x = 0, y = -2, or (0, -2)