3 years ago

At a competition with 8 runners, 2 medals are awarded for first and second

Mathematics

2 answers:

sashaice [31]3 years ago

7 0

Answer:

A. 56

Step-by-step explanation:

You take 8 and then find the next number down and multiply them.

8*7= 56

(Also, I just did this on APEX)

Dafna1 [17]3 years ago

4 0

Answer: Option 'A' is correct.

Step-by-step explanation :

Since we have given that

Number of medals = 2

Number of runners = 8

We need to find the number of ways to award the medals.

We would use "fundamental theorem of counting" to find the number of ways.

So, number of ways is given by

8 × 7 = 56

Hence, option 'A' is correct.

You might be interested in

5 times 3 and 5 over 8 times 9 and 1 over 4

Ber [7]

The answer should be:
20.875

Hope this helps.

3 0

2 years ago

Read 2 more answers

If Cyrus knows that △ABC∼△EDC and AB¯¯¯¯¯¯¯¯∥ED¯¯¯¯¯¯¯¯, how can he prove that line m passing through AB¯¯¯¯¯¯¯¯ has the same sl

Illusion [34]

As AB and ED are parallel, they have the same slope. This means that since lines that are colllinear with parallel segments are parallel, lines l and m are parallel.

4 0

1 year ago

Is 16=3 one, no, or many solutions?

elixir [45]

Answer:

No solutions; parallel

Step-by-step explanation:

The equations x=16 and x=3 both have a slope of 0. So when graphed, they would be parallel and there are no solutions between parallel lines.

3 0

3 years ago

If the area of a circle is 154cm2 what is the radius of that circle

Komok [63]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Evaluate 2x^2+5x^2-5x^3 when x = 2

Margaret [11]

Answer:

question is 2x^2+5x^2-5X^3 if the value of x=2 then we put the value of x in equation= 2(2)^2+5(2)^2-5(2)^3 =2*4+5*4-5*8 = 8+20-40 =28-40 =-12 ans

5 0

3 years ago