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Tom [10]
4 years ago
15

Solving Exponential Equations (lacking a common base) 4^x-5=8

Mathematics
2 answers:
avanturin [10]4 years ago
8 0

Answer:

x= 6 1/2 or 6.5

Step-by-step explanation:

4^x-5 =8

2^2(x-5) =2^3

since the base is equal, the powers are equal

2(x-5) = 3

2x - 10 = 3

2x = 3 + 10

2x = 13

2x/2 = 13/2

x = 6 1/2 or 6.5

Tju [1.3M]4 years ago
6 0

Answer:

6.5

Step-by-step explanation:

4^(x-5) = 8

2^[2(x-5)] = 2³

Equating powers:

2(x-5) = 3

x-5 = 3/2

x = 13/2 or 6½

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S Explain how knowing 50 times 4 =200 helps you find 500 times 400.
Lemur [1.5K]
This is an easy way to solve multiplication with alot of zero's
Add only the numbers, then add the sum of the zeros
So with this problem we do this:-
5*4 is 20, plus the zero in the 50, so the answer is 200
Now we can do the other one:-

5*4 is 20, plus the 4 zeros that we removed is 200,000

Hope I helped. :)
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3 years ago
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saul85 [17]
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4 years ago
Use the graph to approximate the ordered pair where the exponential function begins to exceed the quadratic function.
Ipatiy [6.2K]

Answer:

(4.462, 19.411)

Step-by-step explanation:

From the description, the functions are:

f(x) = (11/5)^(x - 7/10)

g(x) = 1/8x² + 2x + 8

(Notice that 2 2/10 is equivalent to 22/10 = 11/5)

In the picture attached, the plot of the functions is shown. The exponential is in red and the quadratic is in blue. The exponential function begins to exceed the quadratic function from point (4.462, 19.411)

3 0
3 years ago
2(r–2)≥8<br> jdjdhjdhjhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh
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5 0
3 years ago
There are 90 fifth grade students going on a feild trip each student gives teacher 9.25 to cover admission to the theater and fo
Ivenika [448]

Answer: Each student will get an amount of $12.75 to spend on lunch.

Step-by-step explanation:

Since we have given that

Number of fifth grade students = 90

Amount given by each student to cover admission to the theater = 9.25

So, Total amount given by all of the students is given by

9.25\times 90=\$832.5

Amount given by all of the students for lunch admission =$315

Total amount submitted by the students to the teacher regarding trip is given by

832.5+315=\$1147.5

So, Each student will get an equal amount to spend on lunch is given by

\frac{1147.5}{90}=\$12.75

Hence, each student will get an amount of $12.75 to spend on lunch.


5 0
3 years ago
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