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3 years ago

find the equation of a line that passes through (2 -1) and ia parallel to y=2x+y-4=0 leave your answer in the form of y=mx+c

Mathematics

1 answer:

Oksanka [162]3 years ago

7 0

Answer:

Y=2x-5

Step-by-step explanation:

Parallel m=2

Y=mx+c

-1=2(2)+c

C=-5

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Solve 2sin2(x) – 5sin(x) – 3 = 0. Let u = sin(x). Which of the following is equivalent to the given equation?

Orlov [11]

Answer:

$x=(-1)^{k+1}\cdot \dfrac{\pi}{6}+\pi k,\ k\in Z$

Step-by-step explanation:

Consider the equation

$2\sin^2x-5\sin x-3=0$

Substitute

$u=\sin x$

into the equation:

$2u^2-5u-3=0$

This is quadratic equation, where

$D=(-5)^2-4\cdot 2\cdot (-3)=25+24=49\\ \\\sqrt{D}=7$

Hence,

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Now, use the substitution again:

1. When $u_1=-\dfrac{1}{2},$ then

$\sin x=-\dfrac{1}{2}\\ \\x=(-1)^k\sin^{-1}\left(-\dfrac{1}{2}\right)+\pi k,\ k\in Z\\ \\x=(-1)^k\cdot \left(-\dfrac{\pi}{6}\right)+\pi k,\ k\in Z\\ \\x=(-1)^{k+1}\cdot \dfrac{\pi}{6}+\pi k,\ k\in Z$

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$\sin x=3$

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nignag [31]

Answer:

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Step-by-step explanation:

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"x " and "y " x = 2*y x is the largest side of the rectangular area

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So the perimeter is L = x + 2*y or L = 4*y

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