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Ber [7]
3 years ago
5

What base makes the equation below true? Note: A number should be entered, not a word.

Mathematics
1 answer:
il63 [147K]3 years ago
6 0

Answer:

4

Step-by-step explanation:

in base 4

21 = (2 * 4) + (1 * 1) = 9

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Waring Bank offers a 5% interest rate on a $4500 loan for a 3-year term. South Bank offers a 5% interest rate on a $4500 loan fo
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4500 times 5% per year for 3 years = (4500*.05)*3 = answer 1

4500 times 5% per year for 4 years = (4500*.05)*4 = answer 2

Answer 2 minus answer 1 = jackpot
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4 years ago
The double number line shows that 444 pounds of almonds cost \$34$34dollar sign, 34.
IgorC [24]

Answer:

$42.5

Step-by-step explanation:

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3 years ago
Which equation can be used to find the measure of angle GFE?
Afina-wow [57]

Answer:

\theta=\cos^{-1}(\frac{11.9}{14.5})

Step-by-step explanation:

From the diagram, .

The side of the triangle with length 11.9 is adjacent to the given angle.

We also know the hypotenuse to be 14.5 units.

We therefore use the cosine ratio to get;

\cos(\theta)=\frac{Adjacent}{Hypotenuse}

\cos(\theta)=\frac{11.9}{14.5}

We take the inverse cosine of both sides to get;

\theta=\cos^{-1}(\frac{11.9}{14.5})

5 0
3 years ago
Read 2 more answers
How should this model be completed to represent 377 ÷ 12?
gogolik [260]

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Determine whether the equation is exact. If it​ is, then solve it. e Superscript t Baseline (7 y minus 3 t )dt plus (2 plus 7 e
umka21 [38]

Answer:

F(t,y)=(2+7e^t)y+3(1-t)e^t +C

Step-by-step explanation:

You have the following differential equation:

e^t(7y-3t)dt+(2+7e^t)dy=0

This equation can be written as:

Mdt+Ndy=0

where

M=e^t(7y-3t)\\\\N=(2+7e^t)

If the differential equation is exact, it is necessary the following:

\frac{\partial M}{\partial y}=\frac{\partial N}{\partial t}

Then, you evaluate the partial derivatives:

\frac{\partial M}{\partial y}=\frac{\partial}{\partial t}e^t(7y-3t)\\\\\frac{\partial M}{\partial t}=7e^t\\\\\frac{\partial N}{\partial t}=\frac{\partial}{\partial t}(2+7e^t)\\\\\frac{\partial N}{\partial t}=7e^t\\\\\frac{\partial M}{\partial t} = \frac{\partial N}{\partial t}

The partial derivatives are equal, then, the differential equation is exact.

In order to obtain the solution of the equation you first integrate M or N:

F(t,y)=\int N \partial y = (2 +7e^t)y+g(t)        (1)

Next, you derive the last equation respect to t:

\frac{\partial F(t,y)}{\partial t}=7ye^t+g'(t)

however, the last derivative must be equal to M. From there you can calculate g(t):

\frac{\partial F(t,y)}{\partial t}=M=(7y-3t)e^t=7ye^t+g'(t)\\\\g'(t)=-3te^t\\\\g(t)=-3\int te^tdt=-3[te^t-\int e^tdt]=-3[te^t-e^t]

Hence, by replacing g(t) in the expression (1) for F(t,y) you obtain:

F(t,y)=(2+7e^t)y+3(1-t)e^t +C

where C is the constant of integration

8 0
4 years ago
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