Answer:
158.76 cm²
Step-by-step explanation:
Quadrilateral ABCD is composed of 2 right triangles
Construct the line BD, then
Δ ABD and Δ BCD are the 2 right triangles.
The area (A) of a triangle is calculated using
A = 
bh ( b is the base and h the perpendicular height )
Δ ABD with b = 18 and h = 7.5
A = × 18 × 7.5 = 9 × 7.5 = 67.5 cm²
Δ BCD with b = 15.6 and h = 11.7
A = × 15.6 × 11.7 = 7.8 × 11.7 = 91.26 cm²
Thus
area of ABCD = 67.5 + 91.26 = 158.76 cm²
Answer:
Equilateral triangles are sometimes
acute triangles.
Scalene triangles are never
acute triangles.
Right triangles are never
acute triangles.
Obtuse triangles are always
isosceles triangles.
Answer:
The possible numbers could be : 4521, 4125, and 2415
Answer:
see below
Step-by-step explanation:
DB = 9 units (by counting)
BA = 12 units (by counting)
DA can be found by using the pythagorean theorem
a^2 +b^2 = c^2
BD^2 + BA^2 = DA ^2
9^2 +12^2 = DA^2
81 +144 = DA^2
225 = DA ^2
Take the square root of each side
sqrt(225) = sqrt(DA^2)
15 = DA
LJ = 3 units (by counting)
JK = 4 units (by counting)
LK can be found by using the pythagorean theorem
a^2 +b^2 = c^2
LJ^2 + JK^2 = LK ^2
3^2 +4^2 = LK^2
9 +116 = LK^2
25 = LK ^2
Take the square root of each side
sqrt(25) = sqrt(LK^2)
5 = LK
Scale factor from BAD to JKL
15 to 5
Divide each side by 5
3 to 1
We multiply by 1/3 to go from the big to small
Answer: (3,8) and 2-,10) or the slope will be 3/2x
