Let the nomber of 2 pointers be x and that of 3 pointers be y, then
2x + 3y = 30 . . . (1)
x = y + 5 . . . (2)
Putting (2) into (1), gives 2(y + 5) + 3y = 30
2y + 10 + 3y = 30
5y = 30 - 10 = 20
y = 20/5 = 4
x = 4 + 5 = 9
Answer:
1. <u>14x</u> and <u>7</u> and <u>9x</u> and <u>3</u>
2. <u>0x</u>
3. <u>4</u>
Step-by-step explanation:
Step 1: Distribute
First, multiply 7 by 2x and 1 to get 14x and 7. Then multiply -3 by 3x and 1 to get -9x and -1
Step 2: Combine like variable terms
Combine 14x, -5x, and -9x, to get 0x.
Step 3: Combine like constant terms
Combine 7 and -3, to get 4.
Answer:
- TU = UV = VW = WT = 8
- WX = UX = 5
- XV = XT = √39
Step-by-step explanation:
At first we should know the following about the rhombus
1) All sides are congruent
2) The diagonals are perpendicular and bisects each other.
Given UV = 8 and WX = 5
So, according to (1)
TU = UV = VW = WT = 8
And according to (2)
WX = UX = 5
And ΔWXV is a right triangle at ∠x
So, XV² = WV² - WX² = 8² - 5² = 64 - 25 = 39
∴XV = √39
So, XV = XT = √39
So, the missing measure of a rhombus are as following:
- TU = UV = VW = WT = 8
- WX = UX = 5
- XV = XT = √39
