3 years ago

The problem is

1 answer:

7 0

$average=\frac{sum\ of\ attendance}{amount\ of\ shows}\\\\
average=3000\\\\
3000=\frac{2580+2920+third\ show}{3}\ \ \ |*3\\
9000=2580+2920+third\ show\\
9000=5500+third\ show\ \ \ |Subtract\ 5500\\
3500=third\ show\\\\
\textbf{3500\ people\ must\ attend\ the\ third\ show.}$

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